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anonymous

  • 5 years ago

use quadratic formula: x^2 - 15 = 3x PLEASE HELP!!!

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  1. anonymous
    • 5 years ago
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    first set = 0 via \[x^2-3x-15=0\] \[(x-5)(x+3)=0\] \[x-5=0\] \[x=5\] or \[x+3=0\] \[x=-3\]

  2. anonymous
    • 5 years ago
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    oops sorry quadratic formula! hello daniel

  3. anonymous
    • 5 years ago
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    my answer is wrong wrong wrong

  4. anonymous
    • 5 years ago
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    \[Quadratic formula: x = (-b \pm \sqrt{b^2-4ac})/2a\] a = 1 b = -3 c = -15 \[x = (3\pm \sqrt{69})/2 \]

  5. anonymous
    • 5 years ago
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    i will bow out and let daniel reply. his answer will be correct. this one does not factor over integer.

  6. anonymous
    • 5 years ago
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    His answer "will be" correct? :D I love you satellite :D

  7. anonymous
    • 5 years ago
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    feeling is mutual (in a platonic kinda way)

  8. anonymous
    • 5 years ago
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    Thanks Guyss =)

  9. anonymous
    • 5 years ago
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    Who the heck is Platonic? Just kidding :D

  10. anonymous
    • 5 years ago
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    a solid fellow

  11. anonymous
    • 5 years ago
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    ^ I was kidding :D

  12. anonymous
    • 5 years ago
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    What's The Final Answer though? i Don't Have A Calculator =/

  13. anonymous
    • 5 years ago
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    x = 5.65331193 or x = -2.65331193

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spraguer (Moderator)
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