anonymous
  • anonymous
use quadratic formula: x^2 - 15 = 3x PLEASE HELP!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
first set = 0 via \[x^2-3x-15=0\] \[(x-5)(x+3)=0\] \[x-5=0\] \[x=5\] or \[x+3=0\] \[x=-3\]
anonymous
  • anonymous
oops sorry quadratic formula! hello daniel
anonymous
  • anonymous
my answer is wrong wrong wrong

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More answers

anonymous
  • anonymous
\[Quadratic formula: x = (-b \pm \sqrt{b^2-4ac})/2a\] a = 1 b = -3 c = -15 \[x = (3\pm \sqrt{69})/2 \]
anonymous
  • anonymous
i will bow out and let daniel reply. his answer will be correct. this one does not factor over integer.
anonymous
  • anonymous
His answer "will be" correct? :D I love you satellite :D
anonymous
  • anonymous
feeling is mutual (in a platonic kinda way)
anonymous
  • anonymous
Thanks Guyss =)
anonymous
  • anonymous
Who the heck is Platonic? Just kidding :D
anonymous
  • anonymous
a solid fellow
anonymous
  • anonymous
^ I was kidding :D
anonymous
  • anonymous
What's The Final Answer though? i Don't Have A Calculator =/
anonymous
  • anonymous
x = 5.65331193 or x = -2.65331193

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