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anonymous
 5 years ago
(4+radical10)(4radical10)???
I Actually need steps On How to Do This, Test tomorrow, Please Help
anonymous
 5 years ago
(4+radical10)(4radical10)??? I Actually need steps On How to Do This, Test tomorrow, Please Help

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply each term in the first by each term in the second. This gives \[4*44*\sqrt{10}+4*\sqrt{10}\sqrt{10}^2=1610=6\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do FOIL: (xy)(x+y) = x*x +x*y  x*y  y*y = x^2 y^2 If x = 4 & y = radical 10 The answer is 4^2 (radical 10)^2 = 1610 = 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What The Monkey Is FOIL?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First items in the brackets Outside items in the brackets Inside items in the brackets Last items in the brackets....its a way to remember how to expand the equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The sqrt x+c * sqrt xc ...that has a name....anyone recall what it is?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What are you talking about: difference of squares?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope the square root version has its own name...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nonsense. \[(a+b)(ab)=a^2b^2\] \[(4+\sqrt{10})(4\sqrt{10})=4^2\sqrt{10}^2=1610=6\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0'foil' is a trick math teachers play on students.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0conjugate...there it is sqrt x+c is the conjugate of sqrt xc....probably the same for squares but it never came up. And I recall it coming up for complex numbers too now that I found it. i+c and ic used to get rid of the complex number. =)
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