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anonymous

  • 5 years ago

how do you u simplify the radical expression 98

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  1. anonymous
    • 5 years ago
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    \[\sqrt{98}=\sqrt{2}*\sqrt{49} = 7\sqrt{2}\]

  2. anonymous
    • 5 years ago
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    I imagine that after answering a bunch of these it becomes automatic but what is the strategy for breaking one of these down?

  3. anonymous
    • 5 years ago
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    The easiest way is prime factorization: ( http://www.mathsisfun.com/prime-factorization.html) You would "prime factorize" the number inside the root to see if it is composed of any prime that has a power of 2 or more Ex. \[98 = 2*7^2\] Since 7 is squared in the prime factorization, we can take the 7 out (because sqrt and ^2 cancel out. However, 2 doesn't cancel out and therefore stays inside the radical. Ex. 2 \[\sqrt{343}\]\[343 = 7^3\] Since 7 is cubed, we can take out the 7, BUT NOT ALL OF IT. Only the 7^2 can come out (or a 7^4, or 7^6), and so the answer is \[7\sqrt{7}\] Does that make more sense?

  4. anonymous
    • 5 years ago
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    I will check out the prime factorization website forthwith =) I have always had to use the guess and get discouraged method in the past.

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