anonymous
  • anonymous
find the average rate from 3 to 5 for the following functions: 9t^2 anyone know it?
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Average rate = use integrals: \[1/(B-A) * \int\limits_{A}^{B} f(x) dx\] B = 5 A = 3\[1/2 * \int\limits_{3}^{5}9t^2 dt = .5*3t^3|_{3}^5 = 147\]
anonymous
  • anonymous
i never heard of that lol im in pre cal dude
anonymous
  • anonymous
Okay, so you could just average the values:\[f(t) = 9t^5\]\[Rate_{average} = f(5)-f(3)/2 = 225-81/2 = 72\]

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anonymous
  • anonymous
isnt it t^2
anonymous
  • anonymous
That's what I meant. I did the calculations right, I just put 9t^5 :D
anonymous
  • anonymous
kk lol

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