## anonymous 5 years ago Fine the inverse of the function. f(x)=square x-9

1. anonymous

$y = x^2 - 9$ To find inverse, switch x & y :$x = y^2 - 9$$y = \pm \sqrt{x-9}$

2. anonymous

how would i write it as f^-1= for x

3. anonymous

$f^{-1} (x) = \pm \sqrt{x-9}$

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