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anonymous
 5 years ago
how do you find the
Geometric sum of 24+12+6+3 . . .
anonymous
 5 years ago
how do you find the Geometric sum of 24+12+6+3 . . .

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If a and b are positive integers such that ab = 125, then (ab)^(a+b4) is equal to ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know what that means haha im super confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Rule of the sum:\[24*\sum_{0}^{\infty} 1/2^n\] Nifty trick for geometric series with initial number a and ratio r:\[24*\sum_{0}^{\infty} 1/2^n = a/(1r) = 24/(11/2) = 48\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well you got the right answer. i just don't understand it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The trick is: \[a*\sum_{0}^{\infty}(r)^n = a/(1r)\] As long as 1 < r < 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's the same thing :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then how did I get 12? hahaha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You multiplied by 1/2 instead of divided 24/(1/2) = 48, not 12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow that was embarassing hahaha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No it isn't. I do that all the time :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i actually need a lot more help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if youve got some extra time :D
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