anonymous
  • anonymous
how do you find the Geometric sum of 24+12+6+3 . . .
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
If a and b are positive integers such that ab = 125, then (a-b)^(a+b-4) is equal to ?
anonymous
  • anonymous
I don't know what that means haha im super confused
anonymous
  • anonymous
Rule of the sum:\[24*\sum_{0}^{\infty} 1/2^n\] Nifty trick for geometric series with initial number a and ratio r:\[24*\sum_{0}^{\infty} 1/2^n = a/(1-r) = 24/(1-1/2) = 48\]

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anonymous
  • anonymous
well you got the right answer. i just don't understand it
anonymous
  • anonymous
The trick is: \[a*\sum_{0}^{\infty}(r)^n = a/(1-r)\] As long as -1 < r < 1
anonymous
  • anonymous
i used S = t1 / 1-r
anonymous
  • anonymous
but i got 12
anonymous
  • anonymous
That's the same thing :D
anonymous
  • anonymous
then how did I get 12? hahaha
anonymous
  • anonymous
You multiplied by 1/2 instead of divided 24/(1/2) = 48, not 12
anonymous
  • anonymous
OHHHHH
anonymous
  • anonymous
wow that was embarassing hahaha
anonymous
  • anonymous
thanks daniel :)
anonymous
  • anonymous
No it isn't. I do that all the time :D
anonymous
  • anonymous
No worries :D
anonymous
  • anonymous
i actually need a lot more help
anonymous
  • anonymous
if youve got some extra time :D

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