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anonymous

  • 5 years ago

how do you find the Geometric sum of 24+12+6+3 . . .

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  1. anonymous
    • 5 years ago
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    If a and b are positive integers such that ab = 125, then (a-b)^(a+b-4) is equal to ?

  2. anonymous
    • 5 years ago
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    I don't know what that means haha im super confused

  3. anonymous
    • 5 years ago
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    Rule of the sum:\[24*\sum_{0}^{\infty} 1/2^n\] Nifty trick for geometric series with initial number a and ratio r:\[24*\sum_{0}^{\infty} 1/2^n = a/(1-r) = 24/(1-1/2) = 48\]

  4. anonymous
    • 5 years ago
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    well you got the right answer. i just don't understand it

  5. anonymous
    • 5 years ago
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    The trick is: \[a*\sum_{0}^{\infty}(r)^n = a/(1-r)\] As long as -1 < r < 1

  6. anonymous
    • 5 years ago
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    i used S = t1 / 1-r

  7. anonymous
    • 5 years ago
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    but i got 12

  8. anonymous
    • 5 years ago
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    That's the same thing :D

  9. anonymous
    • 5 years ago
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    then how did I get 12? hahaha

  10. anonymous
    • 5 years ago
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    You multiplied by 1/2 instead of divided 24/(1/2) = 48, not 12

  11. anonymous
    • 5 years ago
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    OHHHHH

  12. anonymous
    • 5 years ago
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    wow that was embarassing hahaha

  13. anonymous
    • 5 years ago
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    thanks daniel :)

  14. anonymous
    • 5 years ago
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    No it isn't. I do that all the time :D

  15. anonymous
    • 5 years ago
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    No worries :D

  16. anonymous
    • 5 years ago
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    i actually need a lot more help

  17. anonymous
    • 5 years ago
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    if youve got some extra time :D

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