last month it was estimated that a lake contained 3500 rainbow trout. over a three day period a park ranger caught, tagged and realeased 100 fish. then after two weeks for random mixing she caught 100 more rainbow trout & found three of them had tags. a) what's the probability of catching a tagged fish? b) the answer is: you have to assume that the population is 3500, it remians stable & the fish are well mixed. c) based on the number of tagged fish she caught two weeks later whats the park rangers experimental probability? anyone help with a and c pleeeease?<3

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last month it was estimated that a lake contained 3500 rainbow trout. over a three day period a park ranger caught, tagged and realeased 100 fish. then after two weeks for random mixing she caught 100 more rainbow trout & found three of them had tags. a) what's the probability of catching a tagged fish? b) the answer is: you have to assume that the population is 3500, it remians stable & the fish are well mixed. c) based on the number of tagged fish she caught two weeks later whats the park rangers experimental probability? anyone help with a and c pleeeease?<3

Mathematics
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Single Event Probability Formula : Probability of event A that occurs P(A) = n(A) / n(S). Probability of event A that does not occur P(A') = 1 - P(A). Multiple Event Probability Formula : Probability of event A that occurs P(A) = n(A) / n(S). Probability of event A that does not occur P(A') = 1 - P(A). Probability of event B that occurs P(B) = n(B) / n(S). Probability of event B that does not occur P(B') = 1 - P(B). Probability that both the events occur P(A ∩ B) = P(A) x P(B). Probability that either of event occurs P(A ∪ B) = P(A) + P(B) - P(A ∩ B). Conditional Probability P(A | B) = P(A ∩ B) / P(B). where, n(A) - number of occurrence in Event A, n(B) - number of occurrence in Event B, n(S) - total number of possible outcomes.
whaaaaaaaaaat?!
i think reading the last 3 lines should help, then go to the top

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Other answers:

miss taylor..... Probability of event A occuring = n(A)/n(S) n(S) is the total no of outcomes, or in this case the total no of fish..which is 3500 n(a) is the number of tagged fish..no of favorable outcomes..which is 100
so the theoretical probability is 100/3500 = 1/ 35 = 2.86 %
thanks him, i gotta go cause ive been here about 6hrs too tired to sit in front of a computer all day sseyall
thnx...noprobs

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