## anonymous 5 years ago rationalize the denominator 3+√3/4-√3

1. anonymous

multiply the top and bottom by the conjugate of the denominator, which is 4+sqrt3 $\frac{3+\sqrt{3}}{4-\sqrt{3}}*\frac{4+\sqrt{3}}{4+\sqrt{3}}=\frac{15+7\sqrt{3}}{13}$ (some "foiling" omitted)

2. anonymous

it is right but where did you get the 13 from??

3. anonymous

ok, that was part of the omitted foiling, which I'll now show. in the bottom we have $(4-\sqrt{3})(4+\sqrt{3})=16+4\sqrt{3}-4\sqrt{3}-3=16-3=13$

4. anonymous

on the roots cancelled out ...alrighty