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anonymous

  • 5 years ago

IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. If a certain statistician has an IQ of 112, what percent of the population has an IQ less than she does?

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  1. anonymous
    • 5 years ago
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    Doing a z-test, therefore z<((112-100)/15) This gives you your z-value, and so look in the normal tables for Z<0.133333, and you will find that it is P=0.55303 or 55% which ever you prefer, which is the percentage of people who have an IQ less than 112, if it was greater then it would be P=1-0.55303. I hope this helps.

  2. anonymous
    • 5 years ago
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    i figued it out is 79%

  3. zab505
    • 2 years ago
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    @kropot72 Is he right?

  4. kropot72
    • 2 years ago
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    Neither answer is correct.

  5. zab505
    • 2 years ago
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    Ah, um do you understand this one?

  6. kropot72
    • 2 years ago
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    This question on use of tables of random numbers seems to want you to find a method of using the table that results in one of the choices matching the fourth number selected from the table. I got it to work by making two digit numbers from the first and last digits of each of the ten groups of random numbers.

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