## anonymous 5 years ago I'm struggling with an inverse laplace transform: 1/((s^2+1)^2) What I'd normally do is to use the convolution theorem, and get y(t)=sin^2(t), but I'm being a bit of a retard, and can't seem to get my answer to fit with the suggested solution.

1. anonymous

inverse laplace of $1\div(s ^{2}+1)$ is sint using convolution we need to find $\int\limits_{0}^{t} siny \sin(t-y) dy$

2. anonymous

sinAsinB = 1/2[cos(A - B) - cos(A + B)]

3. anonymous

As I suspected, I'm a retard. I forgot to calculate the convolution after I had found the inverse transform. Thanks!

4. anonymous

welcome