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*solutions

x=2

sorry i miss read the question, don't listen to me.

the answer is that there is no real solution. i dont know how to figure that out

so whats the answer?

no real solution

how about x=2 isn't it correct?

if x=2 it gives the equality of that equation
-2-2^2+2=2^2
or -2^2=2^2
or 4=4

no
-2^2=2^2 => -4=4 which is absurd

what is the rule in multiplying two (-)number ?

its not (-2)^2 its -(2^2)

so that is not an exponent?

what are you talking about?

ok shall we say 3^2
so 2 is the exponent of 3.

did this question ever get answered?

It does not appear that it did...
the number of real solutins of the equation \[-2-x^2+x=2^x\]

how did you come up that equation?

I copy and pasted from the original...

so whats your final answer?

I agree with the given, "no real solution"

ok . am,what is real solution all about?

Clearly.