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anonymous
 5 years ago
Some determine for me the roots
x^4 +6x^2 27=0
anonymous
 5 years ago
Some determine for me the roots x^4 +6x^2 27=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0make substitution x^2=y then the eqn. is (y+9)(y3)=0 which gives x=+rt(3),rt(3),3i,3i

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^4+6x^227=(x^2+9)(x^23)=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you working with complex numbers or just real? if real the answers are \[\pm \sqrt{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops sorry saubhik got it already

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh well in real numbers \[x^2+9=0\] has no solution because if you write \[x^2=9\] you are looking for a real number whose square is negative and there isn't one.
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