anonymous
  • anonymous
Some determine for me the roots x^4 +6x^2 -27=0
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
make substitution x^2=y then the eqn. is (y+9)(y-3)=0 which gives x=+rt(3),-rt(3),3i,-3i
anonymous
  • anonymous
\[x^4+6x^2-27=(x^2+9)(x^2-3)=0\]
anonymous
  • anonymous
are you working with complex numbers or just real? if real the answers are \[\pm \sqrt{3}\]

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anonymous
  • anonymous
real no.s
anonymous
  • anonymous
oops sorry saubhik got it already
anonymous
  • anonymous
oh well in real numbers \[x^2+9=0\] has no solution because if you write \[x^2=-9\] you are looking for a real number whose square is negative and there isn't one.

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