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anonymous

  • 5 years ago

Some determine for me the roots x^4 +6x^2 -27=0

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  1. anonymous
    • 5 years ago
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    make substitution x^2=y then the eqn. is (y+9)(y-3)=0 which gives x=+rt(3),-rt(3),3i,-3i

  2. anonymous
    • 5 years ago
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    \[x^4+6x^2-27=(x^2+9)(x^2-3)=0\]

  3. anonymous
    • 5 years ago
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    are you working with complex numbers or just real? if real the answers are \[\pm \sqrt{3}\]

  4. anonymous
    • 5 years ago
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    real no.s

  5. anonymous
    • 5 years ago
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    oops sorry saubhik got it already

  6. anonymous
    • 5 years ago
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    oh well in real numbers \[x^2+9=0\] has no solution because if you write \[x^2=-9\] you are looking for a real number whose square is negative and there isn't one.

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