## anonymous 5 years ago literal equation A=1/3h(a+4b+c) A=20; h=5; a and c =1 solve for b

1. anonymous

literal equation A=1/3h(a+4b+c) A=20; h=5; a and c =1 solve for b I'm really confused now. I've already looked at some examples

2. anonymous

can anyone get me started?

3. anonymous

did any one solve this yet?

4. anonymous

not sure if it was $A=\frac{1}{3}h(a+4b+c)$or $A=\frac{1}{3h(a+4b+c)}$