## anonymous 5 years ago find the limit as x -->2 7/x-2

1. anonymous

would it be 0/0 or undefined

2. anonymous

equation is 7/x-2

3. anonymous

you can also find the limit by derivating the numerator and denominator the derivatives of 7 is 0 and the derivatives of x-2 is 1 therefore the limit would be 0/1 = 0

4. anonymous

IF you're asking about $\lim_{x \rightarrow 2}{7 \over x-2}$, then you can notice that when substituting $$x=2$$, we get a $$0$$ at the denominator. Therefore, the limit is undefined and goes to $$\infty$$ as x approaches $$2^+$$ and $$-\infty$$ as x approaches $$2^-$$.

5. anonymous

AnwarA has the correct approach. So in this case, L'Hopital's rule can't be used to evaluate the limit, as the third post states.