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anonymous
 5 years ago
I have a distance problem and I know the equation is d=rt. I'm just not sure how to solve the problem: A flight crew flew 420 km in 3 h with a tailwind. Flying against the wind, the flight crew flew 440 km in 4 h. Find the rate of the flight crew in calm air and the rate of the wind.
anonymous
 5 years ago
I have a distance problem and I know the equation is d=rt. I'm just not sure how to solve the problem: A flight crew flew 420 km in 3 h with a tailwind. Flying against the wind, the flight crew flew 440 km in 4 h. Find the rate of the flight crew in calm air and the rate of the wind.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the total distance traveled divide by total amount time should give you an average of how much traveled per hour

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it would be 420/3? and 440/4 to get the rate?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since you are looking for a rate of travel in calm air, i think (420+440)/(3+4) should do it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok Thank you so much!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How would I find the rate of the wind?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is the rate of the wind considered same for both cases?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I guess it would be....the answer I get for the first part is 122.8 km/h. Do I use that answer to determine the rate of the wind?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0one way to find out is  since you have the rate of travel at calm wind, you can subtract rate of travel at either tail wind or against the wind from calm wind

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wind=15 km/hr, aircraft speed = 125 km/hr

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i don't think you can just add the rate of travel since the time at which air plane travels is different

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think the rate of wind might be different for both cases

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@robtobey, how did you arrive at 125 km/h = aircraft speed and 15 km/hr = wind? Was the original equation wrong or was mymath wrong? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0msayer3, There is no indication from the problem statement that the wind velocity changed from my point of view.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, that's what i'm wondering.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I will post the solution in a few minutes.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok...thank yo very much

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0r*t = d r = d/t Let x = the wind speed First flight leg: \[r+x==\frac{d}{t}\text{/.} \{d\to 420,t\to 3\} \]r + x = 140 Second flight leg:\[rx=\frac{d}{t}\text{/.} \{d\to 440,t\to 4\} \]r  x = 110 2 r = 140 + 110 r = 125 r + x =140 125 + x = 140 x = 15

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I use Mathematica for the calculations /. means sort or, "replace the symbols as follows"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok...I think I got it now. Thank you again for your help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Glad I could help you out.
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