## anonymous 5 years ago I have a distance problem and I know the equation is d=rt. I'm just not sure how to solve the problem: A flight crew flew 420 km in 3 h with a tailwind. Flying against the wind, the flight crew flew 440 km in 4 h. Find the rate of the flight crew in calm air and the rate of the wind

1. anonymous

Well, assume that the tail wind adds some amount (x) to the rate.

2. anonymous

So instead of the normal equation you have d = (r+x)t for flying with a tailwind, and d = (r-x)t for flying against the wind. Then solve for r and x.

3. anonymous

you could try this. the speed with the tail wind is $\frac{420}{3}=140$ so with the the tailwind they are going 140 kph and against the wind it is $\frac{440}{4}=110$ kph then as popak said, the first speed going is r + x and the speed returning is r - x so $r+x=140$ and $r-x=110$