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anonymous
 5 years ago
Prove that the graph is continuous or not continuous at x = 2.
anonymous
 5 years ago
Prove that the graph is continuous or not continuous at x = 2.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have attached the graph

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and a picture is better, since not everyone has microsoft office

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there the pic is attached

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or even if they do have office, opening docs from unknown sources can sometimes be problematic.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(2) exists (infact f(2) = 4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0to prove: the lefthand limit has to equal the right hand limit at x = 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0how to prive that without actual functions? my best guess is just to point to it on the graph and say, "see! right there"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can send you a similar graph which the teacher gave us to review with

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i got the picture of the graph now; its just that there is no peicewise function defining the curves

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can see what the left and right hand limits are by looking at the graph.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And they aren't both f(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 2^+}f (x)=5\neq \lim_{x \rightarrow 2^}f(x)=2\] Hence f is not continuous at \(x=2\).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A function is continuous about a point p if and only if p in in the domain of f, and the limit from the left = the limit from the right = f(p)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(2) exists (in fact f(2) = 4 is this correct

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sprinkle in some epsilons and deltas for good effect :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0one second i will attach the sample graph she provided i think thats how she wants the answers

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we can see that there for every epsilon in the neighborhood of L can be produced by a delta such that 0<xc<d in the neightborhood of 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0forget this problem adding a new one
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