anonymous
  • anonymous
Prove that the graph is continuous or not continuous at x = 2.
Mathematics
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anonymous
  • anonymous
Prove that the graph is continuous or not continuous at x = 2.
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
i have attached the graph
1 Attachment
amistre64
  • amistre64
its an empty graph
anonymous
  • anonymous
one sec

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amistre64
  • amistre64
and a picture is better, since not everyone has microsoft office
anonymous
  • anonymous
sure one sec
anonymous
  • anonymous
there the pic is attached
1 Attachment
anonymous
  • anonymous
Or even if they do have office, opening docs from unknown sources can sometimes be problematic.
anonymous
  • anonymous
f(2) exists (infact f(2) = 4
amistre64
  • amistre64
to prove: the lefthand limit has to equal the right hand limit at x = 2
amistre64
  • amistre64
how to prive that without actual functions? my best guess is just to point to it on the graph and say, "see! right there"
anonymous
  • anonymous
do you have pdf
amistre64
  • amistre64
no
anonymous
  • anonymous
i can send you a similar graph which the teacher gave us to review with
amistre64
  • amistre64
i got the picture of the graph now; its just that there is no peicewise function defining the curves
anonymous
  • anonymous
You can see what the left and right hand limits are by looking at the graph.
anonymous
  • anonymous
And they aren't both f(-2)
anonymous
  • anonymous
err f(2)
anonymous
  • anonymous
\[\lim_{x \rightarrow 2^+}f (x)=5\neq \lim_{x \rightarrow 2^-}f(x)=2\] Hence f is not continuous at \(x=2\).
anonymous
  • anonymous
k thats one
anonymous
  • anonymous
A function is continuous about a point p if and only if p in in the domain of f, and the limit from the left = the limit from the right = f(p)
anonymous
  • anonymous
f(2) exists (in fact f(2) = 4 is this correct
amistre64
  • amistre64
sprinkle in some epsilons and deltas for good effect :)
anonymous
  • anonymous
one second i will attach the sample graph she provided i think thats how she wants the answers
amistre64
  • amistre64
we can see that there for every epsilon in the neighborhood of L can be produced by a delta such that 0<|x-c|
anonymous
  • anonymous
forget this problem adding a new one

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