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anonymous

  • 5 years ago

need help with limit graph and q's

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  1. anonymous
    • 5 years ago
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    can you see it

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  2. anonymous
    • 5 years ago
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    a) = -1 b = 2

  3. anonymous
    • 5 years ago
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    hmmm I don't think that is right a or b

  4. anonymous
    • 5 years ago
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    what do you think it is

  5. anonymous
    • 5 years ago
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    limit is asking what is the y value as x gets closer to -3 ...a) is asking what is y becoming as x turns into three from the left side. That arrow is definitely not pointing to -1. b) is asking the same thing from the right side that arrow is not pointing at 2.

  6. anonymous
    • 5 years ago
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    x turns to negative 3

  7. anonymous
    • 5 years ago
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    so it should be -1 right?

  8. anonymous
    • 5 years ago
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    -3 looks like a vertical asymptote to me...which x=-3 are you looking at? maybe the graph you posted and the one im seeing are different?

  9. anonymous
    • 5 years ago
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    oooh my mistake

  10. anonymous
    • 5 years ago
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    so - inf

  11. anonymous
    • 5 years ago
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    for a)

  12. anonymous
    • 5 years ago
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    3 for b?

  13. anonymous
    • 5 years ago
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    yes but depending on how your teacher/book are looking at it they may say that the limit is undefined too if you start at x = 0 and move left towards x=-3 what happens to the line with the arrow?

  14. anonymous
    • 5 years ago
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    yeah undefined also

  15. anonymous
    • 5 years ago
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    =) that one is heading to +oo

  16. anonymous
    • 5 years ago
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    so I know you have c) nailed

  17. anonymous
    • 5 years ago
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    and d) for that matter

  18. anonymous
    • 5 years ago
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    c = DNE

  19. anonymous
    • 5 years ago
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    and neg inf

  20. anonymous
    • 5 years ago
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    d = 3

  21. anonymous
    • 5 years ago
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    oh so close....c) is saying if you approach from either direction...so it is + and - infinity depending which side of the line you are on....so undefined probably best. for d) what is y when x=-3?

  22. anonymous
    • 5 years ago
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    d = 3 right

  23. anonymous
    • 5 years ago
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    no =) the arrowy lines don't point at 3 they point at? -oo and +oo.....so .......undefined the lines dont cross x=-3 at all

  24. anonymous
    • 5 years ago
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    alright the next few are tough

  25. anonymous
    • 5 years ago
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    is it all .5?

  26. anonymous
    • 5 years ago
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    e-h

  27. anonymous
    • 5 years ago
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    uh oh I thought there were getting easier... all good

  28. anonymous
    • 5 years ago
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    i - L have a trick to them

  29. anonymous
    • 5 years ago
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    wait so e- h = .5 right?

  30. anonymous
    • 5 years ago
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    indeed you are correct

  31. anonymous
    • 5 years ago
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    cool

  32. anonymous
    • 5 years ago
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    i = 1

  33. anonymous
    • 5 years ago
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    f = 1

  34. anonymous
    • 5 years ago
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    it is always easier when the limits exist i=1 is correct

  35. anonymous
    • 5 years ago
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    well j anyway =)

  36. anonymous
    • 5 years ago
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    right haha

  37. anonymous
    • 5 years ago
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    k also 1

  38. anonymous
    • 5 years ago
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    you on a roll now

  39. anonymous
    • 5 years ago
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    j = dne

  40. anonymous
    • 5 years ago
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    woot

  41. amistre64
    • 5 years ago
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    j should exist; its a onesided limit

  42. anonymous
    • 5 years ago
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    nah it cant its asking for the value at f(0)

  43. anonymous
    • 5 years ago
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    oh right yeah

  44. amistre64
    • 5 years ago
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    j. lim{x ->0+} = ?? its goes to 1

  45. anonymous
    • 5 years ago
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    lets move onto m

  46. anonymous
    • 5 years ago
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    aaak i didnt pay attention to you going back to j I read that as an L

  47. anonymous
    • 5 years ago
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    yep we already got that

  48. anonymous
    • 5 years ago
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    yep me 2

  49. anonymous
    • 5 years ago
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    okies I am at M

  50. anonymous
    • 5 years ago
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    m = 4?

  51. anonymous
    • 5 years ago
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    f = 4

  52. anonymous
    • 5 years ago
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    sorry n = 4

  53. amistre64
    • 5 years ago
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    m=5 if the graph is right

  54. anonymous
    • 5 years ago
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    m != 4 keep in mind the axis are in a funny spot

  55. anonymous
    • 5 years ago
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    yeah

  56. anonymous
    • 5 years ago
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    x=1 looks a lot like that vertical asymptote at -3 to me

  57. anonymous
    • 5 years ago
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    m-p = 4

  58. anonymous
    • 5 years ago
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    I think you are looking at the wrong x=1

  59. anonymous
    • 5 years ago
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    oh hi mistre!

  60. anonymous
    • 5 years ago
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    yep

  61. anonymous
    • 5 years ago
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    m= - inf

  62. anonymous
    • 5 years ago
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    I think so too

  63. anonymous
    • 5 years ago
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    n = - inf

  64. anonymous
    • 5 years ago
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    now we back on track

  65. anonymous
    • 5 years ago
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    o = - inf

  66. anonymous
    • 5 years ago
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    o. oh oh yeah

  67. anonymous
    • 5 years ago
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    and p = dne

  68. anonymous
    • 5 years ago
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    =) you got it now

  69. anonymous
    • 5 years ago
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    only q 2 p 2 go

  70. anonymous
    • 5 years ago
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    q = - .5

  71. anonymous
    • 5 years ago
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    or maybe that should be a t who built this chart anyway?

  72. anonymous
    • 5 years ago
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    r = -.5

  73. anonymous
    • 5 years ago
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    yeah really weird graph

  74. anonymous
    • 5 years ago
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    I buy q=-.5 and r too for that matter

  75. anonymous
    • 5 years ago
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    s = -.5

  76. anonymous
    • 5 years ago
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    yay

  77. anonymous
    • 5 years ago
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    q as well -.5

  78. anonymous
    • 5 years ago
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    t) i mean

  79. anonymous
    • 5 years ago
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    ding you have reached the next level....hehe alphabetically challenged homework

  80. anonymous
    • 5 years ago
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    new graph hold on second

  81. anonymous
    • 5 years ago
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    do you see it

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  82. anonymous
    • 5 years ago
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    limx→2+f(x) =5≠limx→2−f(x)=2

  83. anonymous
    • 5 years ago
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    let me print it out standby

  84. anonymous
    • 5 years ago
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    we need 4 answers

  85. anonymous
    • 5 years ago
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    and im playing world of warcraft too....semester ended monday for me =)

  86. anonymous
    • 5 years ago
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    haha

  87. anonymous
    • 5 years ago
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    are you in hs or college?

  88. anonymous
    • 5 years ago
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    college...again ....

  89. anonymous
    • 5 years ago
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    nice pass time hit the ladies up instead ;)

  90. anonymous
    • 5 years ago
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    but what would my wife think?

  91. anonymous
    • 5 years ago
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    ah never mind then

  92. anonymous
    • 5 years ago
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    f(2) exists (infact f(2) = 4

  93. anonymous
    • 5 years ago
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    we need 4 answers

  94. anonymous
    • 5 years ago
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    f(x) is continuous at 2 i think jump continutity

  95. anonymous
    • 5 years ago
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    so far a)f(x) is continuous at 2 i think jump continutity b) f(2) exists (infact f(2) = 4 c) f(2) = limit x->2 F(x)

  96. anonymous
    • 5 years ago
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    jump continuity is the opposite of continuous though

  97. anonymous
    • 5 years ago
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    so is it continuous?

  98. anonymous
    • 5 years ago
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    I'm a little confused by the notation for the equations...

  99. anonymous
    • 5 years ago
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    check this file out

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  100. anonymous
    • 5 years ago
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    oh i get it as x ->2+ f(x)=5 I was being dense

  101. anonymous
    • 5 years ago
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    thats what the teacher did on her practice pdf

  102. anonymous
    • 5 years ago
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    so i am assuming we need 4 answers

  103. anonymous
    • 5 years ago
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    ok so from the right side of the graph we have a line from +oo to 2 running along y=5

  104. anonymous
    • 5 years ago
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    alright you mean in limit notation

  105. anonymous
    • 5 years ago
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    I'm just graphing it atm....but yes the notation was throwing me off for a moment I mentioned the other night that math was hard enough and typing math made it math^2 from the left side of the graph a horizontal line from -oo, 2 running along y=2 is that what your graph looks like?

  106. anonymous
    • 5 years ago
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    no no dont go by the 2nd attachment that was just an example we are still working on the first

  107. anonymous
    • 5 years ago
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    this one

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  108. anonymous
    • 5 years ago
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    This one limx→2+f(x) =5≠limx→2−f(x)=2

  109. anonymous
    • 5 years ago
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    yeah

  110. anonymous
    • 5 years ago
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    i just pasted the other graph to show you a comparison of what the teacher expects i assume on this one

  111. anonymous
    • 5 years ago
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    since the left and right side limits at 2 are not equal....it is not continuous...or if you are a more graphy person: you can't draw that graph without lifting your pencil

  112. anonymous
    • 5 years ago
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    cool i will figure out the rest enjoy warcraft

  113. anonymous
    • 5 years ago
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    thank you for all your help!

  114. anonymous
    • 5 years ago
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    okay you enjoy limits...bwah haha and the book calculus for dummies really helped me with limits this semester

  115. anonymous
    • 5 years ago
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    cheers man.. take it ez

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