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anonymous
 5 years ago
need help with limit graph and q's
anonymous
 5 years ago
need help with limit graph and q's

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmmm I don't think that is right a or b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you think it is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0limit is asking what is the y value as x gets closer to 3 ...a) is asking what is y becoming as x turns into three from the left side. That arrow is definitely not pointing to 1. b) is asking the same thing from the right side that arrow is not pointing at 2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x turns to negative 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it should be 1 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03 looks like a vertical asymptote to me...which x=3 are you looking at? maybe the graph you posted and the one im seeing are different?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes but depending on how your teacher/book are looking at it they may say that the limit is undefined too if you start at x = 0 and move left towards x=3 what happens to the line with the arrow?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0=) that one is heading to +oo

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so I know you have c) nailed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and d) for that matter

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh so close....c) is saying if you approach from either direction...so it is + and  infinity depending which side of the line you are on....so undefined probably best. for d) what is y when x=3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no =) the arrowy lines don't point at 3 they point at? oo and +oo.....so .......undefined the lines dont cross x=3 at all

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright the next few are tough

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0uh oh I thought there were getting easier... all good

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i  L have a trick to them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait so e h = .5 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0indeed you are correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is always easier when the limits exist i=1 is correct

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0j should exist; its a onesided limit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nah it cant its asking for the value at f(0)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0j. lim{x >0+} = ?? its goes to 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0aaak i didnt pay attention to you going back to j I read that as an L

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep we already got that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0m=5 if the graph is right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0m != 4 keep in mind the axis are in a funny spot

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=1 looks a lot like that vertical asymptote at 3 to me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think you are looking at the wrong x=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or maybe that should be a t who built this chart anyway?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah really weird graph

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I buy q=.5 and r too for that matter

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ding you have reached the next level....hehe alphabetically challenged homework

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0new graph hold on second

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0limx→2+f(x) =5≠limx→2−f(x)=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me print it out standby

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and im playing world of warcraft too....semester ended monday for me =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you in hs or college?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nice pass time hit the ladies up instead ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but what would my wife think?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(2) exists (infact f(2) = 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x) is continuous at 2 i think jump continutity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so far a)f(x) is continuous at 2 i think jump continutity b) f(2) exists (infact f(2) = 4 c) f(2) = limit x>2 F(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0jump continuity is the opposite of continuous though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm a little confused by the notation for the equations...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i get it as x >2+ f(x)=5 I was being dense

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what the teacher did on her practice pdf

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i am assuming we need 4 answers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so from the right side of the graph we have a line from +oo to 2 running along y=5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright you mean in limit notation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm just graphing it atm....but yes the notation was throwing me off for a moment I mentioned the other night that math was hard enough and typing math made it math^2 from the left side of the graph a horizontal line from oo, 2 running along y=2 is that what your graph looks like?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no no dont go by the 2nd attachment that was just an example we are still working on the first

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This one limx→2+f(x) =5≠limx→2−f(x)=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just pasted the other graph to show you a comparison of what the teacher expects i assume on this one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since the left and right side limits at 2 are not equal....it is not continuous...or if you are a more graphy person: you can't draw that graph without lifting your pencil

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cool i will figure out the rest enjoy warcraft

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you for all your help!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay you enjoy limits...bwah haha and the book calculus for dummies really helped me with limits this semester

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cheers man.. take it ez
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