anonymous
  • anonymous
need help with limit graph and q's
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
can you see it
1 Attachment
anonymous
  • anonymous
a) = -1 b = 2
anonymous
  • anonymous
hmmm I don't think that is right a or b

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anonymous
  • anonymous
what do you think it is
anonymous
  • anonymous
limit is asking what is the y value as x gets closer to -3 ...a) is asking what is y becoming as x turns into three from the left side. That arrow is definitely not pointing to -1. b) is asking the same thing from the right side that arrow is not pointing at 2.
anonymous
  • anonymous
x turns to negative 3
anonymous
  • anonymous
so it should be -1 right?
anonymous
  • anonymous
-3 looks like a vertical asymptote to me...which x=-3 are you looking at? maybe the graph you posted and the one im seeing are different?
anonymous
  • anonymous
oooh my mistake
anonymous
  • anonymous
so - inf
anonymous
  • anonymous
for a)
anonymous
  • anonymous
3 for b?
anonymous
  • anonymous
yes but depending on how your teacher/book are looking at it they may say that the limit is undefined too if you start at x = 0 and move left towards x=-3 what happens to the line with the arrow?
anonymous
  • anonymous
yeah undefined also
anonymous
  • anonymous
=) that one is heading to +oo
anonymous
  • anonymous
so I know you have c) nailed
anonymous
  • anonymous
and d) for that matter
anonymous
  • anonymous
c = DNE
anonymous
  • anonymous
and neg inf
anonymous
  • anonymous
d = 3
anonymous
  • anonymous
oh so close....c) is saying if you approach from either direction...so it is + and - infinity depending which side of the line you are on....so undefined probably best. for d) what is y when x=-3?
anonymous
  • anonymous
d = 3 right
anonymous
  • anonymous
no =) the arrowy lines don't point at 3 they point at? -oo and +oo.....so .......undefined the lines dont cross x=-3 at all
anonymous
  • anonymous
alright the next few are tough
anonymous
  • anonymous
is it all .5?
anonymous
  • anonymous
e-h
anonymous
  • anonymous
uh oh I thought there were getting easier... all good
anonymous
  • anonymous
i - L have a trick to them
anonymous
  • anonymous
wait so e- h = .5 right?
anonymous
  • anonymous
indeed you are correct
anonymous
  • anonymous
cool
anonymous
  • anonymous
i = 1
anonymous
  • anonymous
f = 1
anonymous
  • anonymous
it is always easier when the limits exist i=1 is correct
anonymous
  • anonymous
well j anyway =)
anonymous
  • anonymous
right haha
anonymous
  • anonymous
k also 1
anonymous
  • anonymous
you on a roll now
anonymous
  • anonymous
j = dne
anonymous
  • anonymous
woot
amistre64
  • amistre64
j should exist; its a onesided limit
anonymous
  • anonymous
nah it cant its asking for the value at f(0)
anonymous
  • anonymous
oh right yeah
amistre64
  • amistre64
j. lim{x ->0+} = ?? its goes to 1
anonymous
  • anonymous
lets move onto m
anonymous
  • anonymous
aaak i didnt pay attention to you going back to j I read that as an L
anonymous
  • anonymous
yep we already got that
anonymous
  • anonymous
yep me 2
anonymous
  • anonymous
okies I am at M
anonymous
  • anonymous
m = 4?
anonymous
  • anonymous
f = 4
anonymous
  • anonymous
sorry n = 4
amistre64
  • amistre64
m=5 if the graph is right
anonymous
  • anonymous
m != 4 keep in mind the axis are in a funny spot
anonymous
  • anonymous
yeah
anonymous
  • anonymous
x=1 looks a lot like that vertical asymptote at -3 to me
anonymous
  • anonymous
m-p = 4
anonymous
  • anonymous
I think you are looking at the wrong x=1
anonymous
  • anonymous
oh hi mistre!
anonymous
  • anonymous
yep
anonymous
  • anonymous
m= - inf
anonymous
  • anonymous
I think so too
anonymous
  • anonymous
n = - inf
anonymous
  • anonymous
now we back on track
anonymous
  • anonymous
o = - inf
anonymous
  • anonymous
o. oh oh yeah
anonymous
  • anonymous
and p = dne
anonymous
  • anonymous
=) you got it now
anonymous
  • anonymous
only q 2 p 2 go
anonymous
  • anonymous
q = - .5
anonymous
  • anonymous
or maybe that should be a t who built this chart anyway?
anonymous
  • anonymous
r = -.5
anonymous
  • anonymous
yeah really weird graph
anonymous
  • anonymous
I buy q=-.5 and r too for that matter
anonymous
  • anonymous
s = -.5
anonymous
  • anonymous
yay
anonymous
  • anonymous
q as well -.5
anonymous
  • anonymous
t) i mean
anonymous
  • anonymous
ding you have reached the next level....hehe alphabetically challenged homework
anonymous
  • anonymous
new graph hold on second
anonymous
  • anonymous
do you see it
1 Attachment
anonymous
  • anonymous
limx→2+f(x) =5≠limx→2−f(x)=2
anonymous
  • anonymous
let me print it out standby
anonymous
  • anonymous
we need 4 answers
anonymous
  • anonymous
and im playing world of warcraft too....semester ended monday for me =)
anonymous
  • anonymous
haha
anonymous
  • anonymous
are you in hs or college?
anonymous
  • anonymous
college...again ....
anonymous
  • anonymous
nice pass time hit the ladies up instead ;)
anonymous
  • anonymous
but what would my wife think?
anonymous
  • anonymous
ah never mind then
anonymous
  • anonymous
f(2) exists (infact f(2) = 4
anonymous
  • anonymous
we need 4 answers
anonymous
  • anonymous
f(x) is continuous at 2 i think jump continutity
anonymous
  • anonymous
so far a)f(x) is continuous at 2 i think jump continutity b) f(2) exists (infact f(2) = 4 c) f(2) = limit x->2 F(x)
anonymous
  • anonymous
jump continuity is the opposite of continuous though
anonymous
  • anonymous
so is it continuous?
anonymous
  • anonymous
I'm a little confused by the notation for the equations...
anonymous
  • anonymous
check this file out
1 Attachment
anonymous
  • anonymous
oh i get it as x ->2+ f(x)=5 I was being dense
anonymous
  • anonymous
thats what the teacher did on her practice pdf
anonymous
  • anonymous
so i am assuming we need 4 answers
anonymous
  • anonymous
ok so from the right side of the graph we have a line from +oo to 2 running along y=5
anonymous
  • anonymous
alright you mean in limit notation
anonymous
  • anonymous
I'm just graphing it atm....but yes the notation was throwing me off for a moment I mentioned the other night that math was hard enough and typing math made it math^2 from the left side of the graph a horizontal line from -oo, 2 running along y=2 is that what your graph looks like?
anonymous
  • anonymous
no no dont go by the 2nd attachment that was just an example we are still working on the first
anonymous
  • anonymous
this one
1 Attachment
anonymous
  • anonymous
This one limx→2+f(x) =5≠limx→2−f(x)=2
anonymous
  • anonymous
yeah
anonymous
  • anonymous
i just pasted the other graph to show you a comparison of what the teacher expects i assume on this one
anonymous
  • anonymous
since the left and right side limits at 2 are not equal....it is not continuous...or if you are a more graphy person: you can't draw that graph without lifting your pencil
anonymous
  • anonymous
cool i will figure out the rest enjoy warcraft
anonymous
  • anonymous
thank you for all your help!
anonymous
  • anonymous
okay you enjoy limits...bwah haha and the book calculus for dummies really helped me with limits this semester
anonymous
  • anonymous
cheers man.. take it ez

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