need help with limit graph and q's

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need help with limit graph and q's

Mathematics
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can you see it
1 Attachment
a) = -1 b = 2
hmmm I don't think that is right a or b

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Other answers:

what do you think it is
limit is asking what is the y value as x gets closer to -3 ...a) is asking what is y becoming as x turns into three from the left side. That arrow is definitely not pointing to -1. b) is asking the same thing from the right side that arrow is not pointing at 2.
x turns to negative 3
so it should be -1 right?
-3 looks like a vertical asymptote to me...which x=-3 are you looking at? maybe the graph you posted and the one im seeing are different?
oooh my mistake
so - inf
for a)
3 for b?
yes but depending on how your teacher/book are looking at it they may say that the limit is undefined too if you start at x = 0 and move left towards x=-3 what happens to the line with the arrow?
yeah undefined also
=) that one is heading to +oo
so I know you have c) nailed
and d) for that matter
c = DNE
and neg inf
d = 3
oh so close....c) is saying if you approach from either direction...so it is + and - infinity depending which side of the line you are on....so undefined probably best. for d) what is y when x=-3?
d = 3 right
no =) the arrowy lines don't point at 3 they point at? -oo and +oo.....so .......undefined the lines dont cross x=-3 at all
alright the next few are tough
is it all .5?
e-h
uh oh I thought there were getting easier... all good
i - L have a trick to them
wait so e- h = .5 right?
indeed you are correct
cool
i = 1
f = 1
it is always easier when the limits exist i=1 is correct
well j anyway =)
right haha
k also 1
you on a roll now
j = dne
woot
j should exist; its a onesided limit
nah it cant its asking for the value at f(0)
oh right yeah
j. lim{x ->0+} = ?? its goes to 1
lets move onto m
aaak i didnt pay attention to you going back to j I read that as an L
yep we already got that
yep me 2
okies I am at M
m = 4?
f = 4
sorry n = 4
m=5 if the graph is right
m != 4 keep in mind the axis are in a funny spot
yeah
x=1 looks a lot like that vertical asymptote at -3 to me
m-p = 4
I think you are looking at the wrong x=1
oh hi mistre!
yep
m= - inf
I think so too
n = - inf
now we back on track
o = - inf
o. oh oh yeah
and p = dne
=) you got it now
only q 2 p 2 go
q = - .5
or maybe that should be a t who built this chart anyway?
r = -.5
yeah really weird graph
I buy q=-.5 and r too for that matter
s = -.5
yay
q as well -.5
t) i mean
ding you have reached the next level....hehe alphabetically challenged homework
new graph hold on second
do you see it
1 Attachment
limx→2+f(x) =5≠limx→2−f(x)=2
let me print it out standby
we need 4 answers
and im playing world of warcraft too....semester ended monday for me =)
haha
are you in hs or college?
college...again ....
nice pass time hit the ladies up instead ;)
but what would my wife think?
ah never mind then
f(2) exists (infact f(2) = 4
we need 4 answers
f(x) is continuous at 2 i think jump continutity
so far a)f(x) is continuous at 2 i think jump continutity b) f(2) exists (infact f(2) = 4 c) f(2) = limit x->2 F(x)
jump continuity is the opposite of continuous though
so is it continuous?
I'm a little confused by the notation for the equations...
check this file out
1 Attachment
oh i get it as x ->2+ f(x)=5 I was being dense
thats what the teacher did on her practice pdf
so i am assuming we need 4 answers
ok so from the right side of the graph we have a line from +oo to 2 running along y=5
alright you mean in limit notation
I'm just graphing it atm....but yes the notation was throwing me off for a moment I mentioned the other night that math was hard enough and typing math made it math^2 from the left side of the graph a horizontal line from -oo, 2 running along y=2 is that what your graph looks like?
no no dont go by the 2nd attachment that was just an example we are still working on the first
this one
1 Attachment
This one limx→2+f(x) =5≠limx→2−f(x)=2
yeah
i just pasted the other graph to show you a comparison of what the teacher expects i assume on this one
since the left and right side limits at 2 are not equal....it is not continuous...or if you are a more graphy person: you can't draw that graph without lifting your pencil
cool i will figure out the rest enjoy warcraft
thank you for all your help!
okay you enjoy limits...bwah haha and the book calculus for dummies really helped me with limits this semester
cheers man.. take it ez

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