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can you see it

a) = -1
b = 2

hmmm I don't think that is right a or b

what do you think it is

x turns to negative 3

so it should be -1 right?

oooh my mistake

so - inf

for a)

3 for b?

yeah undefined also

=) that one is heading to +oo

so I know you have c) nailed

and d) for that matter

c = DNE

and neg inf

d = 3

d = 3 right

alright the next few are tough

is it all .5?

e-h

uh oh I thought there were getting easier...
all good

i - L have a trick to them

wait so e- h = .5 right?

indeed you are correct

cool

i = 1

f = 1

it is always easier when the limits exist
i=1 is correct

well j anyway =)

right haha

k also 1

you on a roll now

j = dne

woot

j should exist; its a onesided limit

nah it cant its asking for the value at f(0)

oh right yeah

j. lim{x ->0+} = ?? its goes to 1

lets move onto m

aaak i didnt pay attention to you going back to j I read that as an L

yep we already got that

yep me 2

okies I am at M

m = 4?

f = 4

sorry n = 4

m=5 if the graph is right

m != 4 keep in mind the axis are in a funny spot

yeah

x=1 looks a lot like that vertical asymptote at -3 to me

m-p = 4

I think you are looking at the wrong x=1

oh hi mistre!

yep

m= - inf

I think so too

n = - inf

now we back on track

o = - inf

o. oh oh yeah

and p = dne

=) you got it now

only q 2 p 2 go

q = - .5

or maybe that should be a t who built this chart anyway?

r = -.5

yeah really weird graph

I buy q=-.5 and r too for that matter

s = -.5

yay

q as well -.5

t) i mean

ding you have reached the next level....hehe alphabetically challenged homework

new graph hold on second

do you see it

limx→2+f(x) =5≠limx→2−f(x)=2

let me print it out standby

we need 4 answers

and im playing world of warcraft too....semester ended monday for me =)

haha

are you in hs or college?

college...again ....

nice pass time hit the ladies up instead ;)

but what would my wife think?

ah never mind then

f(2) exists (infact f(2) = 4

we need 4 answers

f(x) is continuous at 2 i think jump continutity

jump continuity is the opposite of continuous though

so is it continuous?

I'm a little confused by the notation for the equations...

check this file out

oh i get it as x ->2+ f(x)=5
I was being dense

thats what the teacher did on her practice pdf

so i am assuming we need 4 answers

ok so from the right side of the graph we have a line from +oo to 2 running along y=5

alright you mean in limit notation

no no dont go by the 2nd attachment that was just an example we are still working on the first

this one

This one limx→2+f(x) =5≠limx→2−f(x)=2

yeah

cool i will figure out the rest enjoy warcraft

thank you for all your help!

cheers man.. take it ez