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anonymous
 5 years ago
If 16, x, 9 are the first 3 terms of a geometric sequence, find the exact value of x
can someone tell me how to find it please :)
thanks
anonymous
 5 years ago
If 16, x, 9 are the first 3 terms of a geometric sequence, find the exact value of x can someone tell me how to find it please :) thanks

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[{16 \over x}={x \over 9}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\(x=12\) is also a solution.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.016=4^2 9=3^2 x should be 3.5^2 = 12.25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A geometric sequence is a sequence in which a term \(a_i\) can be found by multiplying the previous term \(a_{i1}\) by some constant \(d\). In our case d could be \(3/4\) or \(3/4\).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0??? i got 3/4 too but thats wrong the right answer is 12 but i dont understand how they got it why did you put it in a fraction???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah x is either \(12\) or \(12\). You get it by solving the equation I put in my first comment.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In a geometric sequence, the quotient of any two consecutive in the sequence must give the same value. So, in our case, \(16/x =x/9\). Solve this equation for x and you will get the answer.
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