anonymous
  • anonymous
Find the area of a regular hexagon with sides 12 ft
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
A = 1/2 ap
anonymous
  • anonymous
Any takers!
anonymous
  • anonymous
Help me....

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radar
  • radar
I'm thinking lol
radar
  • radar
We need to calculate height: The height is \[\sqrt{12^{2}-6^{2}}=\sqrt{144-36}=\sqrt{108}\]
anonymous
  • anonymous
oh thank you radar.... I think this is the last one! Cause I quit! LOL
radar
  • radar
Area for a regular hexagon is: A= 1/2 (6sh) A=.5 x6 x 12 x sqrt 108=374.123 sq ft
radar
  • radar
s is side length, h is height A is area.
anonymous
  • anonymous
ok
amistre64
  • amistre64
you gots it?
anonymous
  • anonymous
shhhh... no lol
amistre64
  • amistre64
hex=6 sides right?
anonymous
  • anonymous
yeppers
amistre64
  • amistre64
360/6 = 60 degrees for central angles then and an outer side at 12; law of cosines modified will give us lengths of sides
amistre64
  • amistre64
12^2 = 2s^2 - 2(s)(s)(cos(60))
amistre64
  • amistre64
144 = 2s^2 (1 - cos(60)) 144/ (1 - cos(60)) = 2s^2 144/ (1 - cos(60)) ---------------- = s^2 2 s = sqrt(all that) lol
anonymous
  • anonymous
yikes not diggin the cos stuff....
amistre64
  • amistre64
6.0726801....
amistre64
  • amistre64
all that does is give me a side to go off of to caluclate the area of one tri and then gonna multiply by 6 for the whole thing
anonymous
  • anonymous
oh danger... I think the answer is going to be ?\[\sqrt{?}\]
anonymous
  • anonymous
lol
amistre64
  • amistre64
it might be :)
anonymous
  • anonymous
is that 6.0726801 the area?
amistre64
  • amistre64
thats the length of a side
anonymous
  • anonymous
ewe
amistre64
  • amistre64
we got an isoceles trianlgle with a base of 12 and a top angle of 60
amistre64
  • amistre64
if I know the length of the sides I can caluclate the area for on tri pieces of the hex
anonymous
  • anonymous
216 square root 3
amistre64
  • amistre64
12^2 = s^2 + s^2 - 2ss cos(60) 144 = 2s^2 - 2s^2 cos(60) 144 = 2s^2(1 - cos(60)) 144 ---------- = 2s^2 (1-2cos(60)) 72 ---------- = s^2 (1-2cos(60)) 72 sqrt[ ----------- ] = s (1-2cos(60))
amistre64
  • amistre64
s*s*sin(60) ---------- = area of tri piece; 6 of those is the whole thing right? 2
anonymous
  • anonymous
right cause its a 6 sided polygon?!
amistre64
  • amistre64
sqrt*sqrt = innards
amistre64
  • amistre64
yes
amistre64
  • amistre64
that 2cos is a typo.... that denom is sposed to be 1-cos(60)
amistre64
  • amistre64
72 sin(60) ------------ = area of tri 2 (1-cos(60)) 36 sin(60) ----------- (1-cos(60)) 36 (sqrt(3)/2) ------------- (1-(1/2))
amistre64
  • amistre64
18 sqrt(3) --------- = 36sqrt(3) right? 1/2
amistre64
  • amistre64
times 6 = 216 sqrt(3)
anonymous
  • anonymous
lol here... A = 1/2 ap A= 1/2 (6sqrt3)(72) 216sqrt3 = 374.1cm sq
anonymous
  • anonymous
YOU GOT IT!!!!!!!!!!!!!
amistre64
  • amistre64
I did lol
anonymous
  • anonymous
and it matches mine :) Good Business! You soooo hired!! LOL
anonymous
  • anonymous
are
amistre64
  • amistre64
yay!!.... and i did it all with one brain cell tied behind my cerebellum ;)
anonymous
  • anonymous
Hilarious!! You rock!
amistre64
  • amistre64
gotta go write some homework.... have fun ;)
anonymous
  • anonymous
thank you!
radar
  • radar
I was right, he got the same answer lol
radar
  • radar
How did it become centimeters, I thought it was 12 ft
anonymous
  • anonymous
ft squared lol
radar
  • radar
Great, good luck with your studies.
anonymous
  • anonymous
ha thanks

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