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anonymous
 5 years ago
2 l x+4 l > 10 solve for X
anonymous
 5 years ago
2 l x+4 l > 10 solve for X

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0theres arent ls haha sorry those are absolute values

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you could tell me how to do it that be great i now i have to divide by 2.... but does that change the signn.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes that is the first step. no it does not change the sign

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0than you have to divide it to two parts. when x>= 4 than the absolute value does nothing so you get x+4 >5 1>x this is contradiction as x cannot be bigger than 4 and smaller than 1 at the same time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whered you get negative one the x will become positive so i wouldnt have to divide right..? then i would have to do this problem again with flipping the sign and negating the 10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the second part is when 4>=x than the absolute value multiplies it by 1 so you get x4>5 x>9 this is another contradiction so I must have done something wrong :) time to double check

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try this: \[x+1=1x=x1\] now you don't have that annoying minus sign in front of the x. \[2x1>10\] \[x1>5\] \[x1>5\]or \[x1<5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is no contradiction. you have two easy inequalities to solve.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Satellite that answer is incorrect this is a muiltiple choice question and the only answers are with 1 and 9 ... there was no need to move the x when its in an absolute value sign the  drops anyway which is where the problem may be with your solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sat it is not x+1 but x+4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hahah thanks Andras that could be the problem as well haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops i read it as \[x+1\] not \[x+4\] i apologize.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah the answer should be x>9 or 1>x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry. messed up by not reading carefully.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the choices are 1<x<9 (x<1) or (x>9) (x<9) or (x>1) (x<1)or(x>9)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanss both for the help :]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[21x+41>10\] Collect like terms on RHS \[62x >10\] Subtract 10 from both sides; \[52x >0\] Add x to both sides \[52>x\] That is;\[x <52\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Those are absolute values... not 1..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got the answer already :]..
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