SOLVE FOR X

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what?
mmm?
\[(1 \ 3)^{4x-1}=3^{x-1}\]

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(1/3)*****
well, you know exponentiation rules, don't you?
not really.. :x
http://en.wikipedia.org/wiki/Exponentiation#Identities_and_properties
x≈0.4
I dont understand what that means can you show me how you got that answer norbeybarajas
http://en.wikipedia.org/wiki/Exponentiation#Identities_and_properties
-________- I dont understand what im looking at when i look at that..
you have to multiply the equation by \(3^{4x-1}\) to get all the x on one side and then you just simplify, until you can take the logarithm.
i still dont understand but thanks
Then show your calculations and where you don't know what to do.
i dont even know how to start the problem..
I just told you.
where are you getting that though you combined both sidfes of the equal sign..
If you multiply both sides by that term you will get just "1" on one side and the terms with x on the other.
I really dont understand what your saying where did you get 3^4x-1 its either 3^x-1 or 1/3^4x-1
\(3^{4x-1} \cdot (\frac{1}{3})^{4x-1} = 1\) that is why you should really look at those rules!
I did/ i am i dont know what im even looking at !!!!! :[ i just need someone to explain it from the first to last step or before i can solve it..
Maybe you should start with some easier exponential calculations then.
This is on a passed regents exam..... i dont even remeber doing this

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