anonymous
  • anonymous
SOLVE FOR X
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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nowhereman
  • nowhereman
what?
anonymous
  • anonymous
mmm?
anonymous
  • anonymous
\[(1 \ 3)^{4x-1}=3^{x-1}\]

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anonymous
  • anonymous
(1/3)*****
nowhereman
  • nowhereman
well, you know exponentiation rules, don't you?
anonymous
  • anonymous
not really.. :x
nowhereman
  • nowhereman
http://en.wikipedia.org/wiki/Exponentiation#Identities_and_properties
anonymous
  • anonymous
x≈0.4
anonymous
  • anonymous
I dont understand what that means can you show me how you got that answer norbeybarajas
anonymous
  • anonymous
http://en.wikipedia.org/wiki/Exponentiation#Identities_and_properties
anonymous
  • anonymous
-________- I dont understand what im looking at when i look at that..
nowhereman
  • nowhereman
you have to multiply the equation by \(3^{4x-1}\) to get all the x on one side and then you just simplify, until you can take the logarithm.
anonymous
  • anonymous
i still dont understand but thanks
nowhereman
  • nowhereman
Then show your calculations and where you don't know what to do.
anonymous
  • anonymous
i dont even know how to start the problem..
nowhereman
  • nowhereman
I just told you.
anonymous
  • anonymous
where are you getting that though you combined both sidfes of the equal sign..
nowhereman
  • nowhereman
If you multiply both sides by that term you will get just "1" on one side and the terms with x on the other.
anonymous
  • anonymous
I really dont understand what your saying where did you get 3^4x-1 its either 3^x-1 or 1/3^4x-1
nowhereman
  • nowhereman
\(3^{4x-1} \cdot (\frac{1}{3})^{4x-1} = 1\) that is why you should really look at those rules!
anonymous
  • anonymous
I did/ i am i dont know what im even looking at !!!!! :[ i just need someone to explain it from the first to last step or before i can solve it..
nowhereman
  • nowhereman
Maybe you should start with some easier exponential calculations then.
anonymous
  • anonymous
This is on a passed regents exam..... i dont even remeber doing this

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