anonymous
  • anonymous
i need help with the following attachment ....
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
What do you need help with specifically. Long problem, has a lot of work on it already?
anonymous
  • anonymous
to check #6 if i did it correctlty?

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anonymous
  • anonymous
Good work, unfortunately some algebra mistakes. When working on an equation, If you do something to one side, you have to do to the other side (all terms). Likewise when you do something to a radical expression p/q; you must do top and bottom.
anonymous
  • anonymous
ahh i see so then that would make it x = 400*666.7?
anonymous
  • anonymous
On your first step you square, square root (400 + x^2) and 1000 but you didn't square 1500. In any event, it is not recommended to go this route. When you want to square to remove radical, you should first isolate the radical to one side and all other terms to the other side. So your first step, it is recommended to multiply through by sq rt (400+x^2) not to remove radical but to cancel it from the denominator.
anonymous
  • anonymous
okay give me a sec and ill do it
anonymous
  • anonymous
so x=(2/3)?
anonymous
  • anonymous
That was a big jump from one step to the next, may be it's right but the next step is \[-1000(\sqrt{400+x ^{2}}) +1500x=0\]
anonymous
  • anonymous
aww no im not right i did something else..okay let me see if i can get it
anonymous
  • anonymous
is the next step moving the "1000" over the "=" sign making it a positive?
anonymous
  • anonymous
You can, but it is just as easy to divide by -1000.
anonymous
  • anonymous
so it just basically cancels out?
anonymous
  • anonymous
\[\sqrt{400+x ^{2}}=(-1500x)/(-1000)\]
anonymous
  • anonymous
wouldnt it be positive 1000?
anonymous
  • anonymous
oh wait nevermind...
anonymous
  • anonymous
would it be -1500x=\[\sqrt{400+x ^{2}}\](-1000) ?
anonymous
  • anonymous
The purpose of doing this is to isolate the radical, then square it and get rid of it\[400+x ^{2}=(9x ^{2})/4\]
anonymous
  • anonymous
how did you get \[(9x ^{2})/4??\]
anonymous
  • anonymous
\[[(-1500x)/(-1000)]^{2}=(15x/10)^{2}=(3x/2)^{2}\]
anonymous
  • anonymous
does x= -31???
anonymous
  • anonymous
I am not confident in your work, you jump too many steps; it's not the way you do mathematics. Work it from there. I'll check it later. It is definitely not -31
anonymous
  • anonymous
okay i went from your step to \[x^{2}=(9^{x ^{2}}-400]??
anonymous
  • anonymous
\[x ^{2}=(9x ^{2}-400)\]
anonymous
  • anonymous
9xsquared /4 that is sorry
anonymous
  • anonymous
i got \[100\sqrt{2}\]
anonymous
  • anonymous
\[x ^{2}-(9x ^{2})/4=-400\]
anonymous
  • anonymous
\[x ^{2}(1-[9/4]=-400\]
anonymous
  • anonymous
\[x ^{2}(-5/4)=-400\]
anonymous
  • anonymous
isee how your getting this:D
anonymous
  • anonymous
\[x ^{2}=400(4/5)\]
anonymous
  • anonymous
now we divide -400 and (-5/4)?
anonymous
  • anonymous
Yes\[x =\sqrt{320}\]\[x =6\sqrt{5}\]
anonymous
  • anonymous
ahhh i had \[\sqrt{200}\] .... boy was i off ... well thank you so much for helping me i have a better understanding for calculus im in 10th grade so im new to this ... you were tons of help ..bye bye?!
anonymous
  • anonymous
Good work, you are doing good. It took years of working with a tutor for me to feel this comfortable.

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