anonymous
  • anonymous
lim x→−3 6x + 18/|x + 3|
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
i got 6 but i think its wrong
amistre64
  • amistre64
the top factors to cancel the bootom
amistre64
  • amistre64
6 is right

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More answers

anonymous
  • anonymous
but what about the absolute value signs
amistre64
  • amistre64
6(x+3) ------ hmm, i think they are the same as a + value here |x+3|
anonymous
  • anonymous
i thought i had to do -x-3, and x+3
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=lim{x+to+-3}%28%286x%2B18%29%2F%28|x%2B3|%29%29
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=lim{x+to+-3}%28%286x%2B18%29%2F%28|x%2B3|%29%29
amistre64
  • amistre64
it cuts the link short...
amistre64
  • amistre64
i see it tho... the limit doesnt exist it says
amistre64
  • amistre64
since the limit is not the same form left and right; no limit exists
anonymous
  • anonymous
okay thanks
amistre64
  • amistre64
those absolutes getcha i fyou dont watch for em
anonymous
  • anonymous
yeah im doing like 40 problems of nothing put absolutes
amistre64
  • amistre64
lol.. good for the practice :)
anonymous
  • anonymous
haha yeah i guess
amistre64
  • amistre64
if you factor it to get the same looking stuff; it tends to wanna break apart at the '0' limit if thats what they are going for
anonymous
  • anonymous
lim x->-7 (7 - (abs of (x))/(7 + x) is this DNE
amistre64
  • amistre64
7 - |x| ------ right? 7+x
anonymous
  • anonymous
yeah
amistre64
  • amistre64
lets see what this does a little bit to the left and right of -7 then
amistre64
  • amistre64
-6.9; what doe we get?
anonymous
  • anonymous
1
amistre64
  • amistre64
ok.. and at 7.1?
amistre64
  • amistre64
-7.1 that is
anonymous
  • anonymous
1
anonymous
  • anonymous
so its 1
amistre64
  • amistre64
thats a good sign; try with smaller numbers to be sure; -6.9999 and -7.0001
amistre64
  • amistre64
the answer is 1 :)
anonymous
  • anonymous
okay that seems much easier than doing it the way my professor said
amistre64
  • amistre64
if the limit on the left and right are the same; then you have the limit; if they differ, no limit ewxists

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