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anonymous

  • 5 years ago

limits and graph need help graph attached

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  1. anonymous
    • 5 years ago
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    hope you guys can see the graph

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  2. anonymous
    • 5 years ago
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    hello a = -1?

  3. anonymous
    • 5 years ago
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    b = 2?

  4. anonymous
    • 5 years ago
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    c = 2?

  5. watchmath
    • 5 years ago
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    b=-1

  6. anonymous
    • 5 years ago
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    hmm why?

  7. watchmath
    • 5 years ago
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    when you tracing your graph as your x moves approaching -3 from the right, the y-value of your graph is getting closer and closer to which number?

  8. anonymous
    • 5 years ago
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    the full dot on top is confusing me

  9. anonymous
    • 5 years ago
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    otherwise i would write -1

  10. watchmath
    • 5 years ago
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    yes, the value of the limit doesn't depends whether if you have a hole or of full circle.

  11. anonymous
    • 5 years ago
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    are c and d = 2? then

  12. watchmath
    • 5 years ago
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    since the limit from the left and right to -3 is -1. Then we say the limit as x approaches -3 is -2. If the limit from the left doesn't agree with the limit from the right then the limit (without left or right) does not exist.

  13. watchmath
    • 5 years ago
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    The full cirlce only concern about the value of the function it self. So in this case you were right, f(-3)=2.

  14. anonymous
    • 5 years ago
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    but c = DNE

  15. anonymous
    • 5 years ago
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    or do they agree?

  16. watchmath
    • 5 years ago
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    No, c) is -1 because a) and b) agree and equal to -1.

  17. anonymous
    • 5 years ago
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    cool

  18. anonymous
    • 5 years ago
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    e = -inf or DNE

  19. anonymous
    • 5 years ago
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    f = +inf pr dne

  20. anonymous
    • 5 years ago
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    g = DNE

  21. anonymous
    • 5 years ago
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    h = Dne?

  22. watchmath
    • 5 years ago
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    That's right. If you are allow to choose -inf and +inf that is the better answer for e and f.

  23. watchmath
    • 5 years ago
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    g is correct

  24. anonymous
    • 5 years ago
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    what about f?

  25. watchmath
    • 5 years ago
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    h is correct too.

  26. anonymous
    • 5 years ago
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    i meant h

  27. watchmath
    • 5 years ago
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    if you can choose +inf choose +inf

  28. anonymous
    • 5 years ago
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    apologize

  29. anonymous
    • 5 years ago
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    i = 1

  30. anonymous
    • 5 years ago
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    j = 1

  31. anonymous
    • 5 years ago
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    k = 1

  32. anonymous
    • 5 years ago
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    L = DNE?

  33. watchmath
    • 5 years ago
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    great for i) j) k) l)

  34. anonymous
    • 5 years ago
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    ah ur back

  35. anonymous
    • 5 years ago
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    m - p = 5

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  36. watchmath
    • 5 years ago
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    good!

  37. anonymous
    • 5 years ago
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    q= - inf or dne, r = -inf or dne s = DNE, t = DNE

  38. watchmath
    • 5 years ago
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    s=-inf too

  39. anonymous
    • 5 years ago
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    right as u said earlier

  40. anonymous
    • 5 years ago
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    hold on posting another but different

  41. watchmath
    • 5 years ago
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    Do it as a new post

  42. anonymous
    • 5 years ago
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    sure

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