A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

some calculus anyone? see pic:

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    im dying!

  2. watchmath
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    interesting problem. I'll come back later if nobody help you :).

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    maybe i should write my progress too \[\tan \Theta =((4m \sin \alpha) \div (m + 4 m \cos \alpha)) +1\] for q a

  4. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the velocity vector of the truck is 4 times the magnitude of the car then right?

  5. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    add the vectors to get the new vector direction

  6. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    < 0, y> <4x,4y> -------- <4x, 5y> right?

  7. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that should be <x,0>

  8. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    new vector is <5x,4y> then

  9. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, now im with you...

  10. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    whenim wring let me know lol

  11. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i had to look at the question again :)

  12. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the new angle they go off in is y over x

  13. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    4y ---- = tan(t) , but how to but that in sin cos? 5x

  14. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y = sin ; and x = cos right?

  15. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah so \[4\sin (\alpha)/4\cos(\alpha)= \tan(\theta)\]

  16. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    truck vector = <4cos(a),4sin(a)> car vecotr = <1,0>

  17. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    add them to get: < 1 , 0 > <4cos(a),4sin(a)> --------------- <4cos(a) +1, 4sin(a)> = new direction

  18. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh, my numer and denom should be reversed

  19. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    which is: tan(t) = 4sin(a)/(4cos(a)+1)

  20. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    b wants you to tell them the velocity, the magnitude, that this new vector is i think

  21. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    try using distance formula with new vector to see

  22. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but tan =cos/sin not tan = sin/cos

  23. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    scalar the inital velocity of each to u perhaps?

  24. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    tan = sin/cos ; always has and always will

  25. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    tan = slope = y/x = sin/cos

  26. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    dam i looked at cot

  27. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    bjargh all i can get is \[d=\sqrt{16\cos^2(\alpha) + 16 \sin^2(\alpha)}\]

  28. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.