any help on #3?? attachment?

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any help on #3?? attachment?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Ohhh haha it wasnt showing on my screen sorry
its hard as heak?
\[-1000 +\frac{1500x}{\sqrt{400+x^2}}=0\]
no #3
whicih #3 then lol
the long paragraph
ooooo.... this one again
ideally when the beach pipe cost equals the sea pipe cost you reach a balance point
b(1000) + s(1500) = Equilibrium we just have to get a formula to equate b and to plug in
s = sqrt(20^2 + (b-x)^2) where b-x is the distance between the rig and the shore pipe
thats about the best i can do for equating the s and b
b(1000) + sqrt(20^2 + (b-x)^2)(1500) = E solve for b right?
yes x is the distance from the oil rigs vertical line to the shoreline..
well it says my answer will be in terms of x?...
maybe better like this tho: when b(1000) = s(1500) b(1000) = sqrt(20^2 + (b-x)^2)(1500) b(1000)/1500 = sqrt(20^2 + (b-x)^2) 2b/3 = sqrt(20^2 + (b-x)^2) ; ^2 both sides
4b^2 ---- = 400 + (b-x)^2 9 4b^2 ----- = 400 + b^2 -2bx +x^2 9 4b^2 = 9(400 + b^2 -2bx +x^2) 4b^2 = 3600 + 9b^2 -18bx +9x^2
4b^2 = 3600 + 9b^2 -18bx +9x^2 0 = (5)b^2 -(18x)b + (9x^2 + 3600) perhaps?
to solve for b we can use the quadratic formula and insert all this other stuff as parameters
18x sqrt(324x^2 - 4(5)(9x^2 + 3600)) --- + ----------------------------- and simplify lol 10 10
sqrt(144x^2 - 72000) looks possible :)
holy bageezus ... i uderstand the transitions and all ..and everything your doing ..but what are parameters?
parameters are just the values we plug into the quadratic formula to make this easier; they relate to the coeffs of the b values
oh okay!.
so we cant reduce the last step by 12 or anything?
sqrt(144x^2 - 72000) the innards here factor to what: sqrt(144(x^2 - 500)) 12 sqrt(x^2 - 500) if i did that part right lol
our options for b are then: 9x 6sqrt(x^2 - 500) -- +- -------------- right? 5 5
would the 500 then be 100?
the 500 cant reduce the way i have it
\[\frac{9x \pm 6 \sqrt{x^2 - 500}}{5}\]
okay so we just add the numerators over 5!...yay!!
if this is b we should be able to add this to x and get 30 right?
OMGEE YES!!!!!
you are amazing!!!!
are you a professor or something?/
just a something....
haha mysterious i understand you a secret agent for the mathematical race of under delinquents?!?!?
haha jk well thanks for the help!!
:) libraries closing soon, so good luck with the rest; and I hope that helped out :)

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