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anonymous

  • 5 years ago

any help on #3?? attachment?

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  1. anonymous
    • 5 years ago
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    Attachment?

  2. anonymous
    • 5 years ago
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    ?

  3. anonymous
    • 5 years ago
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    1 Attachment
  4. anonymous
    • 5 years ago
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    Ohhh haha it wasnt showing on my screen sorry

  5. anonymous
    • 5 years ago
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    its hard as heak?

  6. amistre64
    • 5 years ago
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    \[-1000 +\frac{1500x}{\sqrt{400+x^2}}=0\]

  7. anonymous
    • 5 years ago
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    no #3

  8. amistre64
    • 5 years ago
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    whicih #3 then lol

  9. anonymous
    • 5 years ago
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    the long paragraph

  10. amistre64
    • 5 years ago
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    ooooo.... this one again

  11. amistre64
    • 5 years ago
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    ideally when the beach pipe cost equals the sea pipe cost you reach a balance point

  12. amistre64
    • 5 years ago
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    b(1000) + s(1500) = Equilibrium we just have to get a formula to equate b and to plug in

  13. amistre64
    • 5 years ago
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    s = sqrt(20^2 + (b-x)^2) where b-x is the distance between the rig and the shore pipe

  14. amistre64
    • 5 years ago
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    thats about the best i can do for equating the s and b

  15. amistre64
    • 5 years ago
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    b(1000) + sqrt(20^2 + (b-x)^2)(1500) = E solve for b right?

  16. anonymous
    • 5 years ago
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    yes x is the distance from the oil rigs vertical line to the shoreline..

  17. anonymous
    • 5 years ago
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    well it says my answer will be in terms of x?...

  18. amistre64
    • 5 years ago
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    maybe better like this tho: when b(1000) = s(1500) b(1000) = sqrt(20^2 + (b-x)^2)(1500) b(1000)/1500 = sqrt(20^2 + (b-x)^2) 2b/3 = sqrt(20^2 + (b-x)^2) ; ^2 both sides

  19. amistre64
    • 5 years ago
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    4b^2 ---- = 400 + (b-x)^2 9 4b^2 ----- = 400 + b^2 -2bx +x^2 9 4b^2 = 9(400 + b^2 -2bx +x^2) 4b^2 = 3600 + 9b^2 -18bx +9x^2

  20. amistre64
    • 5 years ago
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    4b^2 = 3600 + 9b^2 -18bx +9x^2 0 = (5)b^2 -(18x)b + (9x^2 + 3600) perhaps?

  21. amistre64
    • 5 years ago
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    to solve for b we can use the quadratic formula and insert all this other stuff as parameters

  22. amistre64
    • 5 years ago
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    18x sqrt(324x^2 - 4(5)(9x^2 + 3600)) --- + ----------------------------- and simplify lol 10 10

  23. amistre64
    • 5 years ago
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    sqrt(144x^2 - 72000) looks possible :)

  24. anonymous
    • 5 years ago
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    holy bageezus ... i uderstand the transitions and all ..and everything your doing ..but what are parameters?

  25. amistre64
    • 5 years ago
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    parameters are just the values we plug into the quadratic formula to make this easier; they relate to the coeffs of the b values

  26. anonymous
    • 5 years ago
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    oh okay!.

  27. anonymous
    • 5 years ago
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    so we cant reduce the last step by 12 or anything?

  28. amistre64
    • 5 years ago
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    sqrt(144x^2 - 72000) the innards here factor to what: sqrt(144(x^2 - 500)) 12 sqrt(x^2 - 500) if i did that part right lol

  29. amistre64
    • 5 years ago
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    our options for b are then: 9x 6sqrt(x^2 - 500) -- +- -------------- right? 5 5

  30. anonymous
    • 5 years ago
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    would the 500 then be 100?

  31. amistre64
    • 5 years ago
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    the 500 cant reduce the way i have it

  32. amistre64
    • 5 years ago
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    \[\frac{9x \pm 6 \sqrt{x^2 - 500}}{5}\]

  33. anonymous
    • 5 years ago
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    okay so we just add the numerators over 5!...yay!!

  34. amistre64
    • 5 years ago
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    if this is b we should be able to add this to x and get 30 right?

  35. anonymous
    • 5 years ago
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    OMGEE YES!!!!!

  36. anonymous
    • 5 years ago
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    you are amazing!!!!

  37. anonymous
    • 5 years ago
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    are you a professor or something?/

  38. amistre64
    • 5 years ago
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    just a something....

  39. anonymous
    • 5 years ago
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    haha mysterious i understand you a secret agent for the mathematical race of under delinquents?!?!?

  40. anonymous
    • 5 years ago
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    haha jk well thanks for the help!!

  41. amistre64
    • 5 years ago
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    :) libraries closing soon, so good luck with the rest; and I hope that helped out :)

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is replying to Can someone tell me what button the professor is hitting...

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