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anonymous
 5 years ago
limits part 2
anonymous
 5 years ago
limits part 2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0graph attached please have a look

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on the top is the question below is similar example need 4 answers

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Is the handwritten argument your answer? That's right!! :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01) f(2) exists (infact f(2) = 4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha thats teachers the one on top is the hw quiz

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1:D Basically you need to compute three things similar to your earlier exercise. Compute the limit from left, right and the value of the function. Is one of them is different then the function is not continuous there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02) lim f(x) does not exist as x > 2 lim f(x) = DNE is that right?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1well the open circle and the fulls circle is above x=1. So you were not looking at the right point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its asking for 2 though that's why I wrote that

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1yes, so don't look at the x=1.

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1hold on the graph for your question is the one on the top right?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Ok, so at x=2 we don't have any problem. There is no hole or jump at x=2. So it is continuous.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0part 2, limit exists from the right but not from the left
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