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on the top is the question below is similar example need 4 answers
Is the handwritten argument your answer? That's right!! :)
1) f(2) exists (infact f(2) = 4)
haha thats teachers the one on top is the hw quiz
:D Basically you need to compute three things similar to your earlier exercise. Compute the limit from left, right and the value of the function. Is one of them is different then the function is not continuous there.
2) lim f(x) does not exist as x -> 2 lim f(x) = DNE is that right?
well the open circle and the fulls circle is above x=1. So you were not looking at the right point.
its asking for 2 though that's why I wrote that
yes, so don't look at the x=1.
hold on the graph for your question is the one on the top right?
Ok, so at x=2 we don't have any problem. There is no hole or jump at x=2. So it is continuous.
part 2, limit exists from the right but not from the left