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anonymous
 5 years ago
need help with continuity of limits graph posted
anonymous
 5 years ago
need help with continuity of limits graph posted

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0top one is question below one is example

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1It seems you didn't understand what I said earlier :). All the limits and f(2)=4 in this case. So the function is continuous.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well here are the tougher q's i dont know if she wants us to graph or not

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04. Find where the Functions are discontinuous. a. F(x) = x + 3/ x2 – 9 b. F(x) = x + 6/ x2 + 36 c. F(x) = 3x  6

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Well you can try by sketching the graphs and see where the function has a hole, jump or asymptote.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i was thinking factoring the denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then it comes out to 0/x3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am horrible at math i will admit i dont know what to do next

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1when you factor you have \(\frac{x+3}{(x+3)(x3)}\). Remember we can't divide by zero. So the function is undefined at x=3 and x=3. Then at those points the function is discontinuous.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0F(x) = x + 6/ x2 + 36 so for this its at x+6 and x6

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1But if you plug in x=6 or 6 to x^2+6 you won't get zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so graph is continous eveywhere
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