## anonymous 5 years ago how would i find the vert. and horz. asymtope of y=5 over x?

1. anonymous

vertical asymptote is where the equation is undefined. $y=\frac{1}{x}$ is not defined at 0 because $\frac{1}{0}$ is not a number. so the vertical asymptote is given by the equation $x=0$ otherwise known as the y- axis. the horizontal asymptote is the line the graph approaches as $x->\infty$ as x gets large $\frac{1}{x}$ gets close to zero. think about $\frac{1}{1000000}=.000001$ likewise $x->-\infty$ y also gets very small. so the horizontal asymptote is the line $y=0$

2. anonymous

find vertical asymptote: set denominator = 0 and solve. horizontal asymptote: a) if the degree of the denominator is greater than the degree of the numerator it is y - 0 b) if the degree of the numerator is bigger there isn't one. c) if the degrees are the same it is y = ratio of leading coefficients.