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anonymous
 5 years ago
f(x)=16x^2 What is the inverse function of.. I need the answer plzzzzzz, assume that all variables are positive. Again, does anyone know the answer? Someone out there is smart, i know there is.......
anonymous
 5 years ago
f(x)=16x^2 What is the inverse function of.. I need the answer plzzzzzz, assume that all variables are positive. Again, does anyone know the answer? Someone out there is smart, i know there is.......

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x = (16y^2) x/16 = (y^2) sqrt(x)/4 = y  sqrt(x)/4 = y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but that would come out to having an i in the final answer correct?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0nah, i made sure that I took out the 1 first to avoid that ...maybe lol let me look at it after drawing it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0maybe i am tired but i think you missed this one.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0oh i miss alot of them ; not just this one lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya, this thing is like impossible, it's a question on my test, what should i write down as the answer?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its x = y^2 but i dont think we can make a function out of it can we?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f says square, then multiply by 16. f inverse says divide by 16, take the square root. should be \[f^{1}(x)=\sqrt{\frac{x}{16}}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we can stick an absolute value in there cant we :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0one to one because they restricted \[x>0\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[y = \frac{\sqrt{x}}{4}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so function is defined only on positive x, and therefore is one to one. range is obviously negative numbers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got f^1=1/4(x) but i know that's wrong......

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no range is negative so domain of inverse is negative numbers

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\sqrt{x}}{4} ; D:(\infty,0]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont have to graph it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0absolute value not necessary just put \[\sqrt{\frac{x}{4}}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=sqrt%28 x%29%2F4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah but that is not the inverse of this function.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this function was restricted to positive x.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it is if we rectric the domain lol; like trig inverse functions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0123456789 are you confused yet?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0very......i'm a high school freshman in algebra 2 honors.... this is like crazy college crap lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me try to xplain. do you know what the graph of \[y=x^2\] looks like?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, it's a prarabola pointing down

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but we arent doing parabloas

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well the point is that since it is a parabola it is not a one to one function so it doesn't have an inverse. but they made it a one to one function by restricting the domain to positive numbers. so your actual graph is not a parabola, it is just the right hand side of the parabola. hterefore it is one to one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the way you do this is write \[y=16x^2\] replace y by x and x by y to get \[x=16y^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then solve for y: \[x=16y^x\] \[\frac{x}{16}=y^2\] \[y=\frac{\sqrt{x}}{16}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0again the typesetting is bad. the square root should be over the whole thing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it should be \[f^{1}(x)=\frac{\sqrt{x}}{4}\] since the square root of 16 is 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and you don't have to worry about \[\sqrt{x}\] being a problem because the range of your original function was negative numbers, so your domain of the inverse is negative numbers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take out the i or leave it in?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x is negative so x is positive so you can take its square root.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0leave it in. the domain of your original function was positive numbers so the range of your inverse must be positive numbers. do not put the minus sign outside. that would make the answer negative.
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