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qgood11

  • 3 years ago

can u cancel out x^2? problem= [(x^2)+2x]/(x^2)-x

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  1. norbeybarajas
    • 3 years ago
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    may be canceled if you were multiplying

  2. qgood11
    • 3 years ago
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    but im dividing woud it still work

  3. ashwinram
    • 3 years ago
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    \[\frac{x^{2}+2x}{x^{2}}-x\]

  4. norbeybarajas
    • 3 years ago
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    not to say that x ^ 2 is not accompanied by x ^ 2 (+) plus sign. example (x ^ 2) 3 / (x ^ 2) 2y = 3/2y

  5. ashwinram
    • 3 years ago
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    If you have: (a + b) / a, you have to distribute the /a over both the numerators. So, it's (a/a) + (b/a). The first a/a cancel out (you get 1) but you still have the second b/a. So it's 1 + (b/a).

  6. ashwinram
    • 3 years ago
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    Likewise, \[(x ^{2} + 2x)/x ^{2}\] will give you \[(x ^{2}/x ^{2}) + (2x/x ^{2})\], and now you simplify.

  7. qgood11
    • 3 years ago
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    \[(x ^{2}+2x)\div(x ^{2}-x)\] is the equation. how would at be simplified?

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