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anonymous

  • 5 years ago

transform cos 38x to functions of 19x

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  1. anonymous
    • 5 years ago
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    have you heard of the trig identy cos(a+b)=cos(a)cos(b)+sin(a)sin(b)? because cos(38x) can be the same as cos(19x+19x) and so a=19x and b=19x

  2. anonymous
    • 5 years ago
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    I Have not heard of that but it makes sense to me. Would that also work to make it a function of 76x?

  3. anonymous
    • 5 years ago
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    \[cos(2x)=1-sin^2(x)\]

  4. anonymous
    • 5 years ago
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    so \[cos(76x)=1-sin^2(38x)\]

  5. anonymous
    • 5 years ago
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    btw calcstud shows how to derive the formula i wrote.

  6. anonymous
    • 5 years ago
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    thank you!

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