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anonymous
 5 years ago
I am confused could some explain this to me: explain how to solve a quadratic equation using the quadratic formula and demonstrate the process
anonymous
 5 years ago
I am confused could some explain this to me: explain how to solve a quadratic equation using the quadratic formula and demonstrate the process

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b + or  \[b \pm \sqrt{b^24ac}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not the top one only the second one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The quadratic formula is used to find the roots of a quadratic equation in standard form. For example, given the quadratic equation: \[1x ^ {2} + 2x + 2 = 0\] a is the coefficient of x^2, which is 1. b is the coefficient of x, which is 2. c is the constant, which is also 2. The quadratic formula itself is: \[(b \pm \sqrt(b ^ {2}  4 ac))/ 2a\] You would substitute the values you have from your equation into the formula, and then get two values. Those two values would be your roots for the quadratic equation. \[((2) \pm \sqrt(2^{2}  4(1)(2)))/ 2(1) \]\[ = 2 \pm \sqrt(4  8) = 2 \pm (\sqrt 4) = 2 \pm 2i\] 2 + 2i would be one solution, 2  2i would be the second.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what does 2i stand for?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, sorry. The i here stands for imaginary, the square root of negative one. I should have came up with a simpler example. In any case, the presence of the i indicates that there are no real roots for the original quadratic equation. You can use an equation that has real roots (e.g., x^2 + 3x + 2 = 0) with the quadratic formula, and the answer you get will be the same thing as the roots you would get from factoring, if your calculations were not incorrect. (x = 2, 1)
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