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wait one moment

\[x \approx4 ; x \approx-3 ; x \approx-1\]

I was a bit complicated

was rectified and that is the correct answer

What about x^4-14x^2+45=0?

wait one moment

factor
(x^2 -5)(x^2 -9)=0
x^2 = 5
x^2 = 9

x=3
x=-3
x=square root(5)
x=-square root(5)

\[\sqrt{5}\approx 2.23 ; -\sqrt{5}\approx - 2.23\]

Could you still factor it if the 14x^2 was 14x^3(in the same problem)?

wait one moment

is very complicated

wait one moment

solve this equation is very long process and I think I'm doing that I have out there in 10%

expected and it started to let me finish lol

Okay, so you get x^3(x-7)=0 and solve the two pieces for the answers?

( x^3 ) (x-7)= 0 ??????

I think that is how I was taught it. Then you get x=7 and x^3 =0