anonymous
  • anonymous
How do you find all the real solutions to x^3-13x-12=0?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
wait one moment
anonymous
  • anonymous
\[x \approx4 ; x \approx-3 ; x \approx-1\]
anonymous
  • anonymous
I was a bit complicated

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anonymous
  • anonymous
was rectified and that is the correct answer
anonymous
  • anonymous
What about x^4-14x^2+45=0?
anonymous
  • anonymous
wait one moment
dumbcow
  • dumbcow
factor (x^2 -5)(x^2 -9)=0 x^2 = 5 x^2 = 9
anonymous
  • anonymous
x=3 x=-3 x=square root(5) x=-square root(5)
anonymous
  • anonymous
\[\sqrt{5}\approx 2.23 ; -\sqrt{5}\approx - 2.23\]
anonymous
  • anonymous
Could you still factor it if the 14x^2 was 14x^3(in the same problem)?
anonymous
  • anonymous
wait one moment
anonymous
  • anonymous
is very complicated
anonymous
  • anonymous
wait one moment
anonymous
  • anonymous
Don't worry about it then. I was just wondering if they could be only one power different or if they could also be two powers away from each other.
anonymous
  • anonymous
solve this equation is very long process and I think I'm doing that I have out there in 10%
anonymous
  • anonymous
expected and it started to let me finish lol
anonymous
  • anonymous
Can you show me the steps to the x^4-7x^3=0 problem? i think I know how to get 7 but I don't know how you got sero as an answer.
anonymous
  • anonymous
only by deduction. in looking for possible solutions when the right side of the expression as a result of 0 in this case is very easy to see that 7 is the only number other than 0 that satisfies this condition and so that the other three answers are 0 and which is a 4-degree equation must give 4 answers
anonymous
  • anonymous
Okay, so you get x^3(x-7)=0 and solve the two pieces for the answers?
anonymous
  • anonymous
( x^3 ) (x-7)= 0 ??????
anonymous
  • anonymous
I think that is how I was taught it. Then you get x=7 and x^3 =0

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