How do you find all the real solutions to x^3-13x-12=0?

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How do you find all the real solutions to x^3-13x-12=0?

Mathematics
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wait one moment
\[x \approx4 ; x \approx-3 ; x \approx-1\]
I was a bit complicated

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was rectified and that is the correct answer
What about x^4-14x^2+45=0?
wait one moment
factor (x^2 -5)(x^2 -9)=0 x^2 = 5 x^2 = 9
x=3 x=-3 x=square root(5) x=-square root(5)
\[\sqrt{5}\approx 2.23 ; -\sqrt{5}\approx - 2.23\]
Could you still factor it if the 14x^2 was 14x^3(in the same problem)?
wait one moment
is very complicated
wait one moment
Don't worry about it then. I was just wondering if they could be only one power different or if they could also be two powers away from each other.
solve this equation is very long process and I think I'm doing that I have out there in 10%
expected and it started to let me finish lol
Can you show me the steps to the x^4-7x^3=0 problem? i think I know how to get 7 but I don't know how you got sero as an answer.
only by deduction. in looking for possible solutions when the right side of the expression as a result of 0 in this case is very easy to see that 7 is the only number other than 0 that satisfies this condition and so that the other three answers are 0 and which is a 4-degree equation must give 4 answers
Okay, so you get x^3(x-7)=0 and solve the two pieces for the answers?
( x^3 ) (x-7)= 0 ??????
I think that is how I was taught it. Then you get x=7 and x^3 =0

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