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anonymous
 5 years ago
How do you find all the real solutions to
x^313x12=0?
anonymous
 5 years ago
How do you find all the real solutions to x^313x12=0?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x \approx4 ; x \approx3 ; x \approx1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was a bit complicated

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0was rectified and that is the correct answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What about x^414x^2+45=0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0factor (x^2 5)(x^2 9)=0 x^2 = 5 x^2 = 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=3 x=3 x=square root(5) x=square root(5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{5}\approx 2.23 ; \sqrt{5}\approx  2.23\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Could you still factor it if the 14x^2 was 14x^3(in the same problem)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Don't worry about it then. I was just wondering if they could be only one power different or if they could also be two powers away from each other.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solve this equation is very long process and I think I'm doing that I have out there in 10%

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0expected and it started to let me finish lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you show me the steps to the x^47x^3=0 problem? i think I know how to get 7 but I don't know how you got sero as an answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0only by deduction. in looking for possible solutions when the right side of the expression as a result of 0 in this case is very easy to see that 7 is the only number other than 0 that satisfies this condition and so that the other three answers are 0 and which is a 4degree equation must give 4 answers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, so you get x^3(x7)=0 and solve the two pieces for the answers?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0( x^3 ) (x7)= 0 ??????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think that is how I was taught it. Then you get x=7 and x^3 =0
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