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smurfy14
 5 years ago
[(1/(x^2)1/Y^2)]/[(1/x^2+2/xy+1/y^2)]
plz help! youd be awsome if ya did! (tell me how you get then answer as well, thanks!)
smurfy14
 5 years ago
[(1/(x^2)1/Y^2)]/[(1/x^2+2/xy+1/y^2)] plz help! youd be awsome if ya did! (tell me how you get then answer as well, thanks!)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What are your instructions for this problem?

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0"simplify complex functions"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, I started by multiplying the top and bottom of the complex fraction by the LCD, which is x^2y^2 in this case

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\frac{1}{x^2}\frac{1}{2}}{\frac{1}{x^2}+\frac{2}{xy}+\frac{1}{y^2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0arya has it, just wanted to type it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which came out to (y^2x^2)/(y^2+2xy+x^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, haven't figured out how to type all of the nice equations yet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is a gimmick here. the denominator is \[(\frac{1}{x}+\frac{1}{y})^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the numerator is \[(\frac{1}{x}+\frac{1}{y})(\frac{1}{x}\frac{1}{y})\]

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0can you explain how multiplying the LCD with the second fraction on the bottom came out to be 2xy?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(2/xy)timesx ^{2}y ^{2}=2x ^{2}y ^{2}/xy=2\]

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0idk what to do after (y^2x^2)/(y^2+2xy+x^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ignore my response, it didn't come out quite right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{a^2b^2}{a+2ab+b^2}=\frac{(a+b)(ab)}{(a+b)(a+b)}=\frac{ab}{a+b}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y^2x^2=(yx)(y+x) y^2+2xy+x^2=(y+x)(y+x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\frac{1}{x}\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}\] multiply top an bottom by \[xy\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then we can cancel one of the (y+x)

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok thanks so much! think you could help me with [ab]/[a^1=b^1]

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0imean [ab]/[a^1b^1]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, a^1=1/a and b^1=1/b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does that part make sense?

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0no? so ur saying you just move the 1 to the top and not the a along with it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not quite, lets see if it makes more sense when I type out the whole equation. Hang on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(ab)/(a^1b^1) = (ab)/[(1/a)(1/b)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does that make any more sense or no?

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok ya that makes sense, so you dont move the a with the 1 im guessing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\frac{1}{x^2}\frac{1}{y^2}}{\frac{1}{x^2}+\frac{1}{y^2}+\frac{2}{x y}}=1\frac{2 x}{x+y} \] Both equation sides evaluated at x=11 and y=17 yield the value 3/14. Note: The first "y" from left to right in the problem expression text string is a cap y, Y, not lower case y. Mathematica views the two as different characters. The cap Y was changed to lower case prior to solving the problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not quite sure what you mean

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0hah nevermind i got it you can keep going :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Cool, so then just like the previous problem the next step is to multiply the to and bottom by the LCD, which in this case is ab

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0how do you figure out the denominator?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got (ab)ab for the numerator and ba for the denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To get the denominator: (1/a1/b)ab (the LCD)=ab/aab/b=ba

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0ok got it so how did you get the numerator?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just multiplied (ab) by the LCD: ab and got (ab)ab

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0oh duh lol so would you simplify that farther?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, at this point the equation looks like [(ab)ab]/(ba) and if we factor out 1 from the denominator we get [(ab)ab]/[(ab)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then the (ab) cancels and we get ab

smurfy14
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok thank you soo much!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No problem, glad I could help! :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\frac{1}{x^2}\frac{1}{y^2}}{\frac{1}{x^2}+\frac{1}{y^2}+\frac{2}{x y}}=\frac{\frac{x^2+y^2}{x^2 y^2}}{\frac{x^2+2 x y+y^2}{x^2 y^2}}=\frac{x^2+y^2}{x^2+2 x y+y^2}=\frac{((xy) )}{(x+y)}=\frac{x+y}{x+y}\]\[1\frac{2 x}{x+y}=\frac{x+y}{x+y} \]
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