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Do you know how to factor either denominator?

oh (x-1)(x+1) & then it'd be (x-2)(x+1) ?

Yes.

(x-1 ) (x+ 3)

Very good!

Now I got to multiply the 5 by (x+3) right to make it like dem and then the 6(x+2)

& thank you :D

You are correct.
& your're very welcome.

You're better than my teacher! haha, let me work it out and see what I get

Thanks.

on top :5x+15-6x+12
bottom (x-1)(x+2)(x+3)

-x+27 ?

The bottom is correct.

On top: (5x+15) - (6x+12)
Do you see how that will change your answer a little?

I factor?!

5(x+3) 6(x+2)

Sorry. That was not what I was trying to say.
The minus gets distributed to the 6x and the 12.

oh wait that takes me back to the step before :/

oh yeah

So instead of 5x + 15 - 6x +12, we should have
5x + 15 - 6x - 12.

-x-3 ?

-x + 3

oh cause the 15 is positive

Correct

the x+3 doesn't cancel right, because it has a - infront

Correct. Nothing cancels.

:D

(x^3a+1 y^3b+4) / (y^2b-3 x^2a-1) Sorry! I really want to ace this test :(

Is 3a the first exponent?

yes
x^3a+1 the 3a+1 is the exponent

Oh. That makes more sense.

Oh yeah then the 3a+1/2a-1 =

3a-2a and then 1-(-1)

Right?

Yes. The x-exponent would be
(3a+1)-(2a-1) = 3a+1-2a+1 = a+2

okay so then 3b+4-2b-3 = b+1

x^a+2 y^b+1 right?

Remember to distribute the minus to the -3.
4-(-3) = 4+3 = 7

o0oo yeah, then x^a+2 y^b+7

Yes.

I am going to go. Good luck on your test.

Thank you appreciate it!

You're very welcome.