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anonymous

  • 5 years ago

5/x^2+x-2 - 6/x^2+2x-3 Reduce to the lowest terms, simplify.

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  1. anonymous
    • 5 years ago
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    Please use parentheses, it really helps clarify which parts of the expression go together in fractions. I'm assuming the expression is (5 / (x^2 + x - 2)) - (6 / (x^2 + 2x - 3)).

  2. Stacey
    • 5 years ago
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    Do you know how to factor either denominator?

  3. anonymous
    • 5 years ago
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    Sorry, & yeah that's how the expression is. & hm let me try I tried (x+1)(x+1)(x-1) for x^2+x-2 It doesn't look right to me.

  4. Stacey
    • 5 years ago
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    It's not. Since we have x^2, we will only have two parenthesis. Also the third term being negative tells us that we have a plus and a minus. So we know that it factors into (x-__)(x+__)

  5. anonymous
    • 5 years ago
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    oh (x-1)(x+1) & then it'd be (x-2)(x+1) ?

  6. Stacey
    • 5 years ago
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    To get a -2, we need the blanks must multiply to be 2, but add to be the middle number. For example: (x-1)(x+2)=x^2 + x - 2 because -1*2=-2 and -1 + 2 = 1

  7. anonymous
    • 5 years ago
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    oh yeah that makes sense. so for the other equation it has to add up to multiply to -3 but add up to 2 right

  8. anonymous
    • 5 years ago
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    Yes.

  9. anonymous
    • 5 years ago
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    (x-1 ) (x+ 3)

  10. Stacey
    • 5 years ago
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    Very good!

  11. anonymous
    • 5 years ago
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    Now I got to multiply the 5 by (x+3) right to make it like dem and then the 6(x+2)

  12. anonymous
    • 5 years ago
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    & thank you :D

  13. Stacey
    • 5 years ago
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    You are correct. & your're very welcome.

  14. anonymous
    • 5 years ago
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    You're better than my teacher! haha, let me work it out and see what I get

  15. Stacey
    • 5 years ago
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    Thanks.

  16. anonymous
    • 5 years ago
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    on top :5x+15-6x+12 bottom (x-1)(x+2)(x+3)

  17. anonymous
    • 5 years ago
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    -x+27 ?

  18. Stacey
    • 5 years ago
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    The bottom is correct.

  19. Stacey
    • 5 years ago
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    On top: (5x+15) - (6x+12) Do you see how that will change your answer a little?

  20. anonymous
    • 5 years ago
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    I factor?!

  21. anonymous
    • 5 years ago
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    5(x+3) 6(x+2)

  22. Stacey
    • 5 years ago
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    Sorry. That was not what I was trying to say. The minus gets distributed to the 6x and the 12.

  23. anonymous
    • 5 years ago
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    oh wait that takes me back to the step before :/

  24. anonymous
    • 5 years ago
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    oh yeah

  25. Stacey
    • 5 years ago
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    So instead of 5x + 15 - 6x +12, we should have 5x + 15 - 6x - 12.

  26. anonymous
    • 5 years ago
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    -x-3 ?

  27. Stacey
    • 5 years ago
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    -x + 3

  28. anonymous
    • 5 years ago
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    oh cause the 15 is positive

  29. Stacey
    • 5 years ago
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    Correct

  30. anonymous
    • 5 years ago
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    the x+3 doesn't cancel right, because it has a - infront

  31. Stacey
    • 5 years ago
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    Correct. Nothing cancels.

  32. anonymous
    • 5 years ago
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    :D

  33. anonymous
    • 5 years ago
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    (x^3a+1 y^3b+4) / (y^2b-3 x^2a-1) Sorry! I really want to ace this test :(

  34. Stacey
    • 5 years ago
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    Is 3a the first exponent?

  35. anonymous
    • 5 years ago
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    yes x^3a+1 the 3a+1 is the exponent

  36. Stacey
    • 5 years ago
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    Oh. That makes more sense.

  37. Stacey
    • 5 years ago
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    When we divide with variables that are the same, we can subtract exponents. For example, x^12/x^3 = x^(12-3) = x^9

  38. anonymous
    • 5 years ago
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    Oh yeah then the 3a+1/2a-1 =

  39. anonymous
    • 5 years ago
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    3a-2a and then 1-(-1)

  40. anonymous
    • 5 years ago
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    Right?

  41. Stacey
    • 5 years ago
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    Yes. The x-exponent would be (3a+1)-(2a-1) = 3a+1-2a+1 = a+2

  42. anonymous
    • 5 years ago
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    okay so then 3b+4-2b-3 = b+1

  43. anonymous
    • 5 years ago
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    x^a+2 y^b+1 right?

  44. Stacey
    • 5 years ago
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    Remember to distribute the minus to the -3. 4-(-3) = 4+3 = 7

  45. anonymous
    • 5 years ago
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    o0oo yeah, then x^a+2 y^b+7

  46. Stacey
    • 5 years ago
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    Yes.

  47. Stacey
    • 5 years ago
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    I am going to go. Good luck on your test.

  48. anonymous
    • 5 years ago
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    Thank you appreciate it!

  49. Stacey
    • 5 years ago
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    You're very welcome.

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