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moongazer
 5 years ago
The equation of a circle center at the origin and radius 1is ?
moongazer
 5 years ago
The equation of a circle center at the origin and radius 1is ?

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moongazer
 5 years ago
Best ResponseYou've already chosen the best response.0explain why please ill give you a medal if you explained it well

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there isnt anyway of explaining it really lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the general form a circle with centre (a,b) and radius r is \[(xa)^2 +(yb)^2 =r^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here centre is (0,0) yeh.. theres not alot of explaining, you have to remember the formula , thats all you can do

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok lets go back to geometry definition

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh its phytagorus , yeh

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a circle is a set of points such that, the distance from the center is fixed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a circle is a locus of points whose distance from a point is constant, that distance is the radius

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats the ancient greek definition, going back when

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now fast forward to cartesian world, we have x y graph

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your center lets say for convenience is origin (0,0)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your doing it the really long way, not very good explaination lol

moongazer
 5 years ago
Best ResponseYou've already chosen the best response.0ok but please explain easier to understand

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0he wants a thorough explanation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we want d( (x,y) (0,0) = r

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the distance between (0,0) and the points (x,y) to be the constant radius

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so far? , and we know the distance between any two points using the distance formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0elec, this is not easy to understand? i can show a graph , but this interface sucks balls

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can just go straight to the general case centre (a,b) \[\sqrt{(xa)^2 +(yb)^2} = r \]

moongazer
 5 years ago
Best ResponseYou've already chosen the best response.0please explain it like you are explaining it to a kid

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then square both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0d ( (x1,y1) (x2,y2) ) = sqrt ( (x1x2)^2 + (y1y2)^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the distance between any arbitrary center (h,k) and the points (x,y) is some distance r. d ( h,k)(x,y) = r

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0, so sqrt ( (xh)^2 + ( y  k)^2) = r

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is a deductive proof my friend :)

moongazer
 5 years ago
Best ResponseYou've already chosen the best response.0my teacher gave me a really easy solution for this and i just forgot it and then i wrote the equation x^2+y^2=r^2 and i forgot what it means

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you draw a line from your center to a point on the circle, and then draw a triangle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you get pythagorean triangle

moongazer
 5 years ago
Best ResponseYou've already chosen the best response.0please don't give me a complicated solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok youre annoying, bye

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then the world ends tomorrow

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0brb, i will use a whiteboard , this is no good

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a more interesting question has peaked my curiosity, brb

moongazer
 5 years ago
Best ResponseYou've already chosen the best response.0ill just give you both a medal^_^

moongazer
 5 years ago
Best ResponseYou've already chosen the best response.0for answering and explaining^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0complex numbers: find a, b such that (bi)^2 = a^2 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this question is ambiguous, ok one sec

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here click on this http://www.twiddla.com/542364

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0circle centre (2,3), radius 2

moongazer
 5 years ago
Best ResponseYou've already chosen the best response.0it is alright know^_^
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