moongazer
  • moongazer
The equation of a circle center at the origin and radius 1is ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
x^2 +y^2 =1
moongazer
  • moongazer
explain why please ill give you a medal if you explained it well
anonymous
  • anonymous
there isnt anyway of explaining it really lol

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anonymous
  • anonymous
the general form a circle with centre (a,b) and radius r is \[(x-a)^2 +(y-b)^2 =r^2\]
anonymous
  • anonymous
here centre is (0,0) yeh.. theres not alot of explaining, you have to remember the formula , thats all you can do
anonymous
  • anonymous
i can explain
anonymous
  • anonymous
ok lets go back to geometry definition
anonymous
  • anonymous
you there?
moongazer
  • moongazer
ok
anonymous
  • anonymous
ohh its phytagorus , yeh
moongazer
  • moongazer
yes
anonymous
  • anonymous
the locus definition
anonymous
  • anonymous
a circle is a set of points such that, the distance from the center is fixed
anonymous
  • anonymous
right
anonymous
  • anonymous
a circle is a locus of points whose distance from a point is constant, that distance is the radius
anonymous
  • anonymous
thats the ancient greek definition, going back when
anonymous
  • anonymous
now fast forward to cartesian world, we have x y graph
anonymous
  • anonymous
your center lets say for convenience is origin (0,0)
anonymous
  • anonymous
ok so far?
anonymous
  • anonymous
your doing it the really long way, not very good explaination lol
anonymous
  • anonymous
ill do it
moongazer
  • moongazer
ok but please explain easier to understand
anonymous
  • anonymous
he wants a thorough explanation
anonymous
  • anonymous
we want d( (x,y) (0,0) = r
anonymous
  • anonymous
the distance between (0,0) and the points (x,y) to be the constant radius
anonymous
  • anonymous
ok so far? , and we know the distance between any two points using the distance formula
anonymous
  • anonymous
elec, this is not easy to understand? i can show a graph , but this interface sucks balls
anonymous
  • anonymous
you can just go straight to the general case centre (a,b) \[\sqrt{(x-a)^2 +(y-b)^2} = r \]
moongazer
  • moongazer
please explain it like you are explaining it to a kid
anonymous
  • anonymous
then square both sides
anonymous
  • anonymous
d ( (x1,y1) (x2,y2) ) = sqrt ( (x1-x2)^2 + (y1-y2)^2)
anonymous
  • anonymous
right that works
moongazer
  • moongazer
WAIT!
anonymous
  • anonymous
so the distance between any arbitrary center (h,k) and the points (x,y) is some distance r. d ( h,k)(x,y) = r
anonymous
  • anonymous
, so sqrt ( (x-h)^2 + ( y - k)^2) = r
anonymous
  • anonymous
this is a deductive proof my friend :)
moongazer
  • moongazer
my teacher gave me a really easy solution for this and i just forgot it and then i wrote the equation x^2+y^2=r^2 and i forgot what it means
moongazer
  • moongazer
on my ntbk
anonymous
  • anonymous
if you draw a line from your center to a point on the circle, and then draw a triangle
anonymous
  • anonymous
you get pythagorean triangle
moongazer
  • moongazer
please don't give me a complicated solution
anonymous
  • anonymous
ok youre annoying, bye
moongazer
  • moongazer
then?
moongazer
  • moongazer
youre doing it right
anonymous
  • anonymous
then what?
anonymous
  • anonymous
lols
anonymous
  • anonymous
then the world ends tomorrow
anonymous
  • anonymous
brb, i will use a whiteboard , this is no good
moongazer
  • moongazer
ahhhh ok
anonymous
  • anonymous
a more interesting question has peaked my curiosity, brb
moongazer
  • moongazer
ill just give you both a medal^_^
moongazer
  • moongazer
for answering and explaining^_^
anonymous
  • anonymous
complex numbers: find a, b such that (-bi)^2 = a^2 ?
anonymous
  • anonymous
this question is ambiguous, ok one sec
anonymous
  • anonymous
here click on this http://www.twiddla.com/542364
moongazer
  • moongazer
what is this?
anonymous
  • anonymous
circle centre (2,3), radius 2
anonymous
  • anonymous
its pretty basic
moongazer
  • moongazer
it is alright know^_^

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