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anonymous
 5 years ago
complex numbers: find a, b such that (bi)^2 = a^2 ?
anonymous
 5 years ago
complex numbers: find a, b such that (bi)^2 = a^2 ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a^2+b^2=0; a=m+ni b=p+qi (m+ni)^2+(p+qi)^2=0 m^2+p^2=n^2+q^2....(1) mn=pq;....(2) now choose m,n,p,q such that the conditions 1,2 satisfied simultaneously....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are a and b complex numbers ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get mn = pq

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry that will be mn=pq.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0also you foiled wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(m+ni)^2+(p+qi)^2 = m^2 + 2mni n^2 + p^2 + 2pqi  q^2 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where is 2mni and 2pqi

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in your algebra , i dont see it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have done it in single step.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry im doing another problem, helping student, one sec

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont follow your logic

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok then mn = pq, agreed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0something tells me that a,b are integers though originally

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0btw: a and b are real

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the correct answer is: a=b?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0our guy here thinks that a and b are complex numbers , i thought this was simpler, lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the question is: find a and b (both real) such that (bi)^2 = a^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if a, b are not complex then the relation (a)^2=(bi)^2 does not hold.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0see your question starts with "complex numbers". so i thought that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this equation only have a trivial solution..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why a = b = 0? is it because a^2 + b^2 = 0 + 0i?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the question is more interesting if you allow a and b to be complex , right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for real no. only a=b=0 holds

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a^2 = (b*i)^2 = b^2*i^2 = b^2 *1 ,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you find any such a,b other than 0 that holds your condition????????????????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so a^2 = b^2 , so a^2 + b^2 = 0,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no because a^2>=0 , and b^2 >= 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0see i think a,b must be considered as complex otherwise its very easy....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just solve the damn equation, lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you take them complex then also you will find a solution 0+0i along with some new solution...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so this equation is equilvalent, find all a,b, such that a^2 + b^2 = 0, for a,b element of C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0damn...i have another typo: (bi)^2 = a^2...therefore b^2 = a^2  so the solution is a = b?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0noooooooooooooooooooooooooooooooooo

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(bi)^2 does not mean (bi)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0find a and b (both real) such that (bi)^2 = a^2.......this is the correct problem statement.....sorry....
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