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anonymous
 5 years ago
can someone help me with qs 4 please???
anonymous
 5 years ago
can someone help me with qs 4 please???

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0from this link http://www.ocr.org.uk/download/pp_10_jun/ocr_57857_pp_10_jun_gce_475201.pdf

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can find the actuallyy functions for them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because you know f(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0F(x)=(x^25x) f(2x)=(4x^210x)=4x(x2.5) now the intersection points will be 0 and 2.5 instead of 0,5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for 3f(x) you have to multiply 3 with the ordinates of that points. Now you can draw it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the multiply by 3 would it be 3x^215x???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but that o and 5 again and in the mark scheme it says minimum points and there different to 0, 2.5 and 0,5
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