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## anonymous 5 years ago can someone help me with qs 4 please???

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1. anonymous

$\sqrt{4}?$

2. anonymous
3. anonymous

I don't know sorry

4. anonymous

you can find the actuallyy functions for them

5. anonymous

because you know f(x)

6. anonymous

F(x)=(x^2-5x) f(2x)=(4x^2-10x)=4x(x-2.5) now the intersection points will be 0 and 2.5 instead of 0,5

7. anonymous

for 3f(x) you have to multiply 3 with the ordinates of that points. Now you can draw it.

8. anonymous

the multiply by 3 would it be 3x^2-15x???

9. anonymous

yes.

10. anonymous

but that o and 5 again and in the mark scheme it says minimum points and there different to 0, 2.5 and 0,5

11. anonymous

im confused :S

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