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anonymous

  • 5 years ago

can someone help me with qs 4 please???

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  1. anonymous
    • 5 years ago
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    \[\sqrt{4}?\]

  2. anonymous
    • 5 years ago
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    from this link http://www.ocr.org.uk/download/pp_10_jun/ocr_57857_pp_10_jun_gce_475201.pdf

  3. anonymous
    • 5 years ago
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    I don't know sorry

  4. anonymous
    • 5 years ago
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    you can find the actuallyy functions for them

  5. anonymous
    • 5 years ago
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    because you know f(x)

  6. anonymous
    • 5 years ago
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    F(x)=(x^2-5x) f(2x)=(4x^2-10x)=4x(x-2.5) now the intersection points will be 0 and 2.5 instead of 0,5

  7. anonymous
    • 5 years ago
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    for 3f(x) you have to multiply 3 with the ordinates of that points. Now you can draw it.

  8. anonymous
    • 5 years ago
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    the multiply by 3 would it be 3x^2-15x???

  9. anonymous
    • 5 years ago
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    yes.

  10. anonymous
    • 5 years ago
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    but that o and 5 again and in the mark scheme it says minimum points and there different to 0, 2.5 and 0,5

  11. anonymous
    • 5 years ago
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    im confused :S

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spraguer (Moderator)
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