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moongazer

  • 5 years ago

In a geometric series, the second term is 3 and the fifth term is 81. Find the third term. (please explain clearly and easy to understand if you did that i'll give you a medal)

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  1. anonymous
    • 5 years ago
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    no more circles, lol

  2. anonymous
    • 5 years ago
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    moon, go to school, lol

  3. anonymous
    • 5 years ago
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    hi dipan

  4. anonymous
    • 5 years ago
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    ill go back, one sec

  5. anonymous
    • 5 years ago
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    ar=3 ar^4=81 r=3 a=1 third term ar^2=9

  6. anonymous
    • 5 years ago
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    ar = 3, how do you know r = 3

  7. moongazer
    • 5 years ago
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    lol you are here again

  8. anonymous
    • 5 years ago
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    i dont think this is right

  9. anonymous
    • 5 years ago
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    ar^4/(ar)=27 r^3=27 r=3...

  10. anonymous
    • 5 years ago
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    do it step by step.....

  11. moongazer
    • 5 years ago
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    the answer is 9

  12. anonymous
    • 5 years ago
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    oh youre right

  13. anonymous
    • 5 years ago
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    nice :)

  14. anonymous
    • 5 years ago
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    moongazer... i have given the ans....

  15. anonymous
    • 5 years ago
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    give him medal :)

  16. moongazer
    • 5 years ago
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    i am really confused with geometric and arithmetic series questions do you have tips to be good at it??

  17. anonymous
    • 5 years ago
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    geometric series is given by ar^n. where a is the first term and r is the common ratio. In AP the series is like a+nd. where d is the common difference.

  18. anonymous
    • 5 years ago
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    in geometric when we divide consecutive terms, it is constant hence the term ratio

  19. anonymous
    • 5 years ago
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    in arithmetic when we subtract terms we get a constant difference

  20. moongazer
    • 5 years ago
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    i already know that geometric series common ratio and arithmetic is common difference i am just confused

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