In a geometric series, the second term is 3 and the fifth term is 81. Find the third term.
(please explain clearly and easy to understand if you did that i'll give you a medal)

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- moongazer

- schrodinger

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- anonymous

no more circles, lol

- anonymous

moon, go to school, lol

- anonymous

hi dipan

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## More answers

- anonymous

ill go back, one sec

- anonymous

ar=3
ar^4=81
r=3
a=1
third term ar^2=9

- anonymous

ar = 3, how do you know r = 3

- moongazer

lol you are here again

- anonymous

i dont think this is right

- anonymous

ar^4/(ar)=27
r^3=27
r=3...

- anonymous

do it step by step.....

- moongazer

the answer is 9

- anonymous

oh youre right

- anonymous

nice :)

- anonymous

moongazer... i have given the ans....

- anonymous

give him medal :)

- moongazer

i am really confused with geometric and arithmetic series questions do you have tips to be good at it??

- anonymous

geometric series is given by ar^n. where a is the first term and r is the common ratio. In AP the series is like a+nd. where d is the common difference.

- anonymous

in geometric when we divide consecutive terms, it is constant
hence the term ratio

- anonymous

in arithmetic when we subtract terms we get a constant difference

- moongazer

i already know that geometric series common ratio and arithmetic is common difference i am just confused

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