moongazer
  • moongazer
In a geometric series, the second term is 3 and the fifth term is 81. Find the third term. (please explain clearly and easy to understand if you did that i'll give you a medal)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
no more circles, lol
anonymous
  • anonymous
moon, go to school, lol
anonymous
  • anonymous
hi dipan

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anonymous
  • anonymous
ill go back, one sec
anonymous
  • anonymous
ar=3 ar^4=81 r=3 a=1 third term ar^2=9
anonymous
  • anonymous
ar = 3, how do you know r = 3
moongazer
  • moongazer
lol you are here again
anonymous
  • anonymous
i dont think this is right
anonymous
  • anonymous
ar^4/(ar)=27 r^3=27 r=3...
anonymous
  • anonymous
do it step by step.....
moongazer
  • moongazer
the answer is 9
anonymous
  • anonymous
oh youre right
anonymous
  • anonymous
nice :)
anonymous
  • anonymous
moongazer... i have given the ans....
anonymous
  • anonymous
give him medal :)
moongazer
  • moongazer
i am really confused with geometric and arithmetic series questions do you have tips to be good at it??
anonymous
  • anonymous
geometric series is given by ar^n. where a is the first term and r is the common ratio. In AP the series is like a+nd. where d is the common difference.
anonymous
  • anonymous
in geometric when we divide consecutive terms, it is constant hence the term ratio
anonymous
  • anonymous
in arithmetic when we subtract terms we get a constant difference
moongazer
  • moongazer
i already know that geometric series common ratio and arithmetic is common difference i am just confused

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