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anonymous
 5 years ago
If y=cos x then f'(3pi/4) is?
anonymous
 5 years ago
If y=cos x then f'(3pi/4) is?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{\sqrt{2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it should be +ve 1/root2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the slope of the tangent is negative at the reqd point in the graph of f(x)=cosx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, its 1/rt(2). u r right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok how did you get it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in the interval (pi/2,pi) the function is f(x)=+cosx so its derivative is sinx and at 3pi/4 its value is 1/rt(2). Observe that i had to find the sign of the function in the neighbourhood of the given point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=cos x in the intervl pi/2 to pi

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes... so the value is positive.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean when u plug pi/2 in f(x), f(x) comes positive

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=cosx in pi/2 to pi derivative of cosx is sinx so f'(x)=sinx
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