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anonymous
 5 years ago
I've tried to answer this, but I just don't seem to get the right equation to begin with. Help, please?
The distance between city A and city B is 280 km. If in going from city A to B, a car traveled 30 kph faster than usual, the trip would've required 3 hours less than the usual time. Find the original speed of the car.
Thank you!! <3
anonymous
 5 years ago
I've tried to answer this, but I just don't seem to get the right equation to begin with. Help, please? The distance between city A and city B is 280 km. If in going from city A to B, a car traveled 30 kph faster than usual, the trip would've required 3 hours less than the usual time. Find the original speed of the car. Thank you!! <3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{280}{u}\frac{280}{u+30}=3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hi! Could you also explain how you came up with the equation? Thank you! :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0original speed=\[40 km/h\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since distance = speed * t so... Time=d/s so,(280/x)  (280/x+30)= 3 so, Time  Time = Time :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hi phoebeco. understood ?? Medel plz :) :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0distance/original speed=time taken before increasing speed. distance/increased speed=time taken after increasing speed subtraction yields 3hrs. as per question.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0plz contribute to my medel.... have none :( inspire me to help by giving medel

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you guys, so much!! :) well explained!
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