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anonymous

  • 5 years ago

I've tried to answer this, but I just don't seem to get the right equation to begin with. Help, please? The distance between city A and city B is 280 km. If in going from city A to B, a car traveled 30 kph faster than usual, the trip would've required 3 hours less than the usual time. Find the original speed of the car. Thank you!! <3

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  1. anonymous
    • 5 years ago
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    \[\frac{280}{u}-\frac{280}{u+30}=3\]

  2. anonymous
    • 5 years ago
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    Hi! Could you also explain how you came up with the equation? Thank you! :)

  3. anonymous
    • 5 years ago
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    distance/speed=time

  4. anonymous
    • 5 years ago
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    original speed=\[40 km/h\]

  5. anonymous
    • 5 years ago
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    since distance = speed * t so... Time=d/s so,(280/x) - (280/x+30)= 3 so, Time - Time = Time :)

  6. anonymous
    • 5 years ago
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    Hi phoebeco. understood ?? Medel plz :) :)

  7. anonymous
    • 5 years ago
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    distance/original speed=time taken before increasing speed. distance/increased speed=time taken after increasing speed subtraction yields 3hrs. as per question.

  8. anonymous
    • 5 years ago
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    plz contribute to my medel.... have none :( inspire me to help by giving medel

  9. anonymous
    • 5 years ago
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    hope u r inspired:)

  10. anonymous
    • 5 years ago
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    :) yes...........

  11. anonymous
    • 5 years ago
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    thank you guys, so much!! :) well explained!

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