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anonymous
 5 years ago
How to check AT SIGHT whether a limit exists or not? for ex.: lim(x>2){5/(rt(2)rt(x))}
anonymous
 5 years ago
How to check AT SIGHT whether a limit exists or not? for ex.: lim(x>2){5/(rt(2)rt(x))}

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05  if the top can cancel out the offending bottom sqrt(2)  sqrt(x) then we can control the function There is no way for '5' to control the bottom of this

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there is a vertical asymptote at 2; not a hole.... if we had a whole, a limit would exist; if we had a hole we could rewrite it to an equavilant form without a hole

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if both sides of the asymptote go to the same infinity tho, we might be justified in saying the limit is + infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0left hand limit goes to infty and right hand limit is +infty. therefore limit doesn't exist. Now considering asymptotes is not "at sight" mathematics!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0PS:u are not given the graph of this function

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0asymptotes is 'at sight' when you know what to look for in the equation...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a vertical asymptote occurs when you cant eliminate the offending zero by a like term in the numerator

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 9  has an issue qt 3; but that issue is resolved by the top (x+3)(x+2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x+3)(x3)  ; the (x+3)s cancel out and we are left with just a hole (x+3)(x+2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if there is no way to control the offending zero in the bottom; we get an asymptote...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0even if there is an asymptote how will you say both parts of the curve go to same infty i.e. both go to +infty/infty or one goes to + and other to infty?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a sign chart helps :) You know what the zeros are; so plot out there signs on a chart and you will see which side is neg and pos

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if there is only one zero; its most likely opposites, but that aint a general rule because its determined by the equation

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0<..... 2 ......>  0 +  inf VA inf ; for this one tho
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