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anonymous

  • 5 years ago

cos. of 23 degrees?

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  1. anonymous
    • 5 years ago
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    cos(a-b) = cosa cosb + sina sinb cos(a+b) = cosa cosb - sina sinb cos23 = cos(60-37) cos(60-37) = cos60 cos37 + sin60 sin37 = (1/2)(4/5) + (sqrt of 3 /2) (3/5)

  2. anonymous
    • 5 years ago
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    \[(4/10) + (3\sqrt{3}) /10 = (1/10) (4+3\sqrt{3})\]

  3. anonymous
    • 5 years ago
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    english please? lol ur dealing with a blonde here

  4. anonymous
    • 5 years ago
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    that's the formula you can get \[\cos 23^{o} \] from \[\cos(60^{o}-37^{o})\]

  5. anonymous
    • 5 years ago
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    cos(a-b) = cosa cosb + sina sinb so for cos23 -> cos(60-37) = cos60 cos37 + sin60 sin37 we know that cos60 is 1/2 cos 37 is 4/5 sin 60 is \[\sqrt{3}/2\] and sin 37 is 3/5 then just plug the values of those sin and cosine to the formula

  6. anonymous
    • 5 years ago
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    ...ok

  7. anonymous
    • 5 years ago
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    0.424?

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