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anonymous

  • 5 years ago

if in a triangle ABC, cosA.cosB+sinAsinBsinC=1, then the triangle is a) right angled b) equilateral c)isosceles d)none

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  1. anonymous
    • 5 years ago
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    a) use A=B and C=90 u get (sinA)^2+(cosA)^2=1 which is an identity!

  2. anonymous
    • 5 years ago
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    its not necessary that A should be equal to B right?

  3. anonymous
    • 5 years ago
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    the answer is d

  4. anonymous
    • 5 years ago
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    that gives a 45-90-45 triangle. i JUst tested a PARTICULAR case the answer should hold for all cases!!

  5. anonymous
    • 5 years ago
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    k. then guessing wont work..

  6. anonymous
    • 5 years ago
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    you want to see the solution?

  7. anonymous
    • 5 years ago
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    yups...

  8. anonymous
    • 5 years ago
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    why ask if u know the solution?

  9. anonymous
    • 5 years ago
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    because i dont understand them.

  10. anonymous
    • 5 years ago
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    why dont u use transformation formulae with the result A+B+C=180 that will give you the answer.

  11. anonymous
    • 5 years ago
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    okay i got that one cleared up...thanx

  12. anonymous
    • 5 years ago
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    how?

  13. anonymous
    • 5 years ago
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    jus took out sinC from the relation.. that led to to the conclusion that A=B and finally C=90 the answer should be a its misprinted here i guess

  14. anonymous
    • 5 years ago
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    well guess was right. It had to be right you know!!

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spraguer (Moderator)
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