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y = 3rt(5-x) + 3 ; i assume you wanna invert it x = (5-y)^(1/3) + 3 x-3 = (5-y)^(1/3) (x-3)^3 = 5-y (x-3)^3 -5 = -y -(x-3)^3 +5 = y
This is the help I got, but it's still not correct.
y = 3rt(5-x) + 3 ; x = (5-y)^(1/3) + 3 These two are not same! even not inverses of each other!
I was confused with that. that's what the other tutor person on here sent me.
free helper that is prone to error ;)
I tried to send you a message but you werent on anymore
You're fine to be wrong, I just want to know what I'm doing.
Inverse of f(x)=3rt(5-x)+3 is g(x)=5-(x-3)^3
sorry if you felt I was blaiming
no feelings hurt :)
I put that and it told me that there was a syntax error
y = cbrt(5-x) + 3 ; we can usually find the inverse by swapping x and y ; and resolving for y. x = cbrt(5-y) +3 x-3 = cbrt(5-y) ; ^3 each side... (x-3)^3 = 5-y ; +y and -(x-3)^3 to both sides y = 5 -(x-3)^3 which is exaclty the same as: y = -(x-3)^3 + 5 which sauhkik says aint the solution lol
cbrt(5-y) = (5-y)^(1/3) they are the exact same thing..
Ok, I tried it again and it was happy with it. I must have typed that one wrong or something.
Yeah I know that's the same thing.
:) im glad it worked for you :)
:) this online hmwk may be the end of me..... :p
programs can be sticklers for "do it exactly like i say" mentality lol
It also gets unhappy when simplifying raticals... took me forever figure that one out.
have you tried yelling at it? :)
haha, yeah that has happend. the little thinking dudes in my computer dont seem to hear me....