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anonymous
 5 years ago
Find the equation of the tangent line: yx^2+xy^2=6, (1, 2). Can anyone explain the steps of implicit differentiation?
anonymous
 5 years ago
Find the equation of the tangent line: yx^2+xy^2=6, (1, 2). Can anyone explain the steps of implicit differentiation?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y'x^2+y(2x)+x(2yy')+y^2=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thats the first step right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y'(x^2+2xy)=(2xy+y^2) y'=y(2x+y)/x(x+2y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tangent line is y2=6/5(x1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0On the key it says the slope is 8/5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh mistake in computations

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.08/5 is the right ans

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So implicit differentiation, can you quickly verbally go through it, what steps do you do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for yx^2 use product rule (derivative of y)x^2+(derivative of x^2) y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0similar for the second term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OHHHHH!!!! I SEEEEEEE!!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THANK YOU SO MUCH! I really appreciate it :D
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