Let , x^2+2x, x is > or = to -1.
Find its inverse and state its domain and range using interval notation. If required, use fractions, NOT decimals.
I did quadratic formula and got:
My answer: (-2+-sqrt(4+4x))/2
Domain of : (-oo,-1]
but this answer is wrong, what did I do wrong?

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I put [-1,oo) for range and that was correct...

Yeah, the range is \([-1,\infty)\).

\[\left( -2\pm \sqrt(2^2-4(1)(-1)\right)/2\]
This is my answer if thats clearer

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