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cherrilyn

  • 5 years ago

Determine convergence or divergence and explain which method you used for......

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  1. cherrilyn
    • 5 years ago
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    \[\sum_{n=2}^{\infty} 1/ n \ln n-n\]

  2. anonymous
    • 5 years ago
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    the whole term in in denominator?

  3. cherrilyn
    • 5 years ago
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    no.. sorry I don't know how to make a division sign on here...... but its 1 over nln-n

  4. anonymous
    • 5 years ago
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    thats what i want to confirm

  5. cherrilyn
    • 5 years ago
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    yeah. 1 is in the numerator.

  6. anonymous
    • 5 years ago
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    have u read the integral test for convergence of the series?

  7. cherrilyn
    • 5 years ago
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    If \[\int\limits_{1}^{\infty} f(x)dx\] converges then \[\sum_{n=1}^{\infty} a _{n} \] converges

  8. anonymous
    • 5 years ago
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    right and function must be montonically decreasing

  9. anonymous
    • 5 years ago
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    \[\int\limits_{2}^{\infty} (1/x)/(\ln x-1) dx\]

  10. cherrilyn
    • 5 years ago
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    ?

  11. anonymous
    • 5 years ago
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    solve the integral, the given series converges if the integral converges

  12. anonymous
    • 5 years ago
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    \[\lim t \rightarrow \infty [\ln(lnx-1)] x varies from 2 \to t\]

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